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never [62]
3 years ago
11

Calculate the mass of silver bromide produced from 22.5 g of silver nitrate.

Chemistry
1 answer:
Orlov [11]3 years ago
6 0
Equation is as follow,

<span>                     2 AgNO</span>₃<span>  +  MgBr</span>₂<span>    </span>→    <span>2 AgBr  +  Mg(NO</span>₃<span>)</span>₂

According to eq.

    339.74 g (2 moles) AgNO₃ produces  =  375.54 g (2 moles) of AgBr
So,
                    22.5 g AgNO₃ will produce  =  X g of AgBr

Solving for X,
                             X  =  (22.5 g × 375.54 g) ÷ 339.74 g

                             X  =  24.87 g of AgBr
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2 years ago
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What is formed when water chemically combines with carbon dioxide
solong [7]

When water chemically combines with carbon dioxide, a Carbonic acid is formed.

<u>Explanation</u>:

  • Carbon dioxide responds with water in a solution to form a weak acid, carbonic acid. Carbonic acid disassociates into hydrogen particles and bicarbonate particles. The hydrogen particles and water respond with the most basic minerals modifying the minerals.  
  • Carbon dioxide and the other atmospheric gases disintegrate in surface waters. Dissolved gases are in equilibrium with the gas in the atmosphere. Carbon dioxide responds with water in a solution to form the weak acid, carbonic acid. Carbonic acid disassociates into hydrogen particles and bicarbonate particles.  
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5 0
3 years ago
An ethylene gas torch requires 300 L of gas at 0.8 atm. What will be the pressure of the gas if ethylene is supplied by a 200.0
Vlad [161]

Answer:

1.2 atm

Explanation:

Given data

  • Volume of the gas in the tank (V₁): 200.0 L
  • Pressure of ethylene gas in the tank (P₁): ?
  • Volume of the gas in the torch (V₂): 300 L
  • Pressure of the gas in the torch (P₂): 0.8 atm

If we consider ethylene gas to be an ideal gas, we can find the pressure of ethylene gas in the tank using Boyle's law.

P_1 \times V_1 = P_2 \times V_2\\P_1 = \frac{P_2 \times V_2}{V_1} = \frac{0.8atm \times 300L}{200.0L} = 1.2 atm

3 0
3 years ago
Convert the pressure 525.4 torr to kPa.
Oduvanchick [21]

Answer:

Option A. 70.0 KPa.

Explanation:

Data obtained from the question include:

Pressure (torr) = 525.4 torr

Pressure (kPa) =?

The pressure expressed in torr can be converted kPa as shown below:

760 torr = 101.325 KPa

Therefore,

525.4 torr = (525.4 x 101.325) / 760 = 70.0 KPa.

Therefore, 525.4 torr is equivalent to 70.0 KPa.

3 0
2 years ago
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How many mL of a stock 50% (w/v) KNO3 solution are needed to prepare 250 mL of a 20% (w/v) KNO3 solution?
Andre45 [30]

Answer:

100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.

Explanation:

In the given question it is mentioned that

     S1=50%

      V2=250ml

      S2= 20%

We all know that

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                     ∴V1=  V2S2×1/S1

                      ∴V1= 250×20÷50

                       ∴V1= 100ml

 

6 0
3 years ago
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