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never [62]
3 years ago
11

Calculate the mass of silver bromide produced from 22.5 g of silver nitrate.

Chemistry
1 answer:
Orlov [11]3 years ago
6 0
Equation is as follow,

<span>                     2 AgNO</span>₃<span>  +  MgBr</span>₂<span>    </span>→    <span>2 AgBr  +  Mg(NO</span>₃<span>)</span>₂

According to eq.

    339.74 g (2 moles) AgNO₃ produces  =  375.54 g (2 moles) of AgBr
So,
                    22.5 g AgNO₃ will produce  =  X g of AgBr

Solving for X,
                             X  =  (22.5 g × 375.54 g) ÷ 339.74 g

                             X  =  24.87 g of AgBr
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