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Nataly [62]
3 years ago
8

Which of the following has to happen before the eardrum begins to vibrate with the same frequency as the source of the sound wav

es? A. Vibrations have to be transmitted to the fibers of the auditory nerve. B. Impulses have to be sent to the brain through the auditory nerve. C. The outer ear has to collect the sound waves and lead them to the middle ear. D. The brain has to interpret the direction from which the sounds are being delivered.
Physics
2 answers:
denpristay [2]3 years ago
8 0

Answer: i think its c

djverab [1.8K]3 years ago
4 0

Answer:

C. The outer ear has to collect the sound waves and lead them to the middle ear.

Explanation:

In the process of hearing, the first thing that happens is that sound waves enter the outer ear through a passage called "auditory canal" that reaches the eardrum.

The movement of the incoming sound waves causes the eardrum to vibrate and transmit these vibrations to three tiny bones of the middle ear.

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Which of the following changes will result in a stronger electromagnet?
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The correct option is C. i.e. <span>Using more coils of wire
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3 years ago
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A large fake cookie sliding on a horizontal surface is attached to one end of a horizontal spring with spring constant k = 440 N
irinina [24]

Answer:

a) 0.275 m b) 13.6 J

Explanation:

In absence of friction, the energy is exchanged between the spring (potential energy) and the cookie (kinetic energy), so at any point, the sum of both energies must be the same:

E = ½ kx2 + ½ mv2

If we take as initial state, the instant when the cookie is passing through the spring’s equilibrium position, all the energy is kinetic, and we know that is equal to 20.0 J.

After sliding to the right, while is being acted on by a friction force, it came momentarily at rest. At this point, the initial kinetic energy, has become potential elastic energy, in part, and in thermal energy also, represented by the work done by the friction force.

So, for this state, we can say the following:

Ki = Uf + Eth = ½* k*d2 + Ff*d

20.0J = ½ *440 N/m* d2 + 11.0 *d, where d is the compressed length of the spring, which is equal to the distance travelled by the cookie before coming momentarily at rest.

We have a quadratic equation, that, after simplifying terms, can be solved as follows, applying the quadratic formula:

d = -0.05/2 +/- √0.090625 = -0.025 +/- 0.3 = 0.275 m (we take the positive root)

b) If we take as our new initial status the moment at which the spring is compressed, and the cookie is at rest, all the energy is potential:

E = Ui = 1/2 k d²

In this case, d is the same value that we got in a), i.e., 0.275 m (as the distance travelled by the cookie after going through the equilibrium point is the same length that the spring have been compressed).

E= 1/2 440 N/m . (0.275)m² = 16.6 J

When the cookie passes again through the equilibrium position, the energy will be in part kinetic, and in part, it will have become thermal energy again.

So, we can write the following equation:

Kf = Ui - Ff.d = 16.6 J - 11.0 (0.275) m = 16.6 J - 3.03 J = 13.6 J

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