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Nataly [62]
4 years ago
8

Which of the following has to happen before the eardrum begins to vibrate with the same frequency as the source of the sound wav

es? A. Vibrations have to be transmitted to the fibers of the auditory nerve. B. Impulses have to be sent to the brain through the auditory nerve. C. The outer ear has to collect the sound waves and lead them to the middle ear. D. The brain has to interpret the direction from which the sounds are being delivered.
Physics
2 answers:
denpristay [2]4 years ago
8 0

Answer: i think its c

djverab [1.8K]4 years ago
4 0

Answer:

C. The outer ear has to collect the sound waves and lead them to the middle ear.

Explanation:

In the process of hearing, the first thing that happens is that sound waves enter the outer ear through a passage called "auditory canal" that reaches the eardrum.

The movement of the incoming sound waves causes the eardrum to vibrate and transmit these vibrations to three tiny bones of the middle ear.

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A large 75-kg lighting fixture can be hung from wires of identical size and shape made of aluminum, brass, or copper. The values
marshall27 [118]

Answer:

C. Copper

Explanation:

F = Force on string

L_0 = Intial length of string

A = Area of string

E = Young's modulus of material

Change in length is given by

\Delta L=\frac{FL_0}{AE}

It can be seen that the change in length is inversely proportional to the Young's modulus of the material.

Here

E_a=0.7\times 10^{11}\ Pa

E_b=0.91\times 10^{11}\ Pa

E_c=1.1\times 10^{11}\ Pa

\\\Rightarrow E_c>E_b>E_a

So, copper will stretch the least.

5 0
4 years ago
Which equation represents mass-energy equivalence? E = m2c E = mc2 E = (mc)2 E = mc
motikmotik

Einstein's energy mass equivalence relation say that if the whole given mass is converted to energy then it would be

E = mc^2

where

m = mass in kg

c = speed of light in m/s

this is the origination of quantum physics and by this formula we can relate the dual nature of light and particle

So correct relation above will be

E = mc^2

4 0
4 years ago
Read 2 more answers
he membrane that surrounds a certain type of living cell has a surface area of 6.0 x 10-9 m2 and a thickness of 1.6 x 10-8 m. As
k0ka [10]

Answer:

1.54481175\times 10^{-12}\ C

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

A = Area = 6\times 10^{-9}\ m^2

d = Thickness = 1.6\times 10^{-8}\ m

k = Dielectric constant = 5.4

V = Voltage = 86.2 mV

Charge is given by

Q=CV\\\Rightarrow Q=k\epsilon\dfrac{A}{d}V\\\Rightarrow Q=5.4\times 8.85\times 10^{-12}\times \dfrac{6\times 10^{-9}}{1.6\times 10^{-8}}\times 86.2\times 10^{-3}\\\Rightarrow Q=1.54481175\times 10^{-12}\ C

The charge on the outer surface is 1.54481175\times 10^{-12}\ C

4 0
3 years ago
Which is a compound machine?<br><br> a broom<br> a screwdriver<br> a slide<br> a pair of scissors
8090 [49]
A pair of scissors .....................................
4 0
3 years ago
A straight wire segment 5 m long makes an angle of 30° with a uniform magnetic field of 0.37 T. Find the magnitude of the force
SIZIF [17.4K]

Answer:

The magnitude of the force on the wire is 2.68 N.

Explanation:

Given that,

Length of the wire, L = 5 m

Magnetic field, B = 0.37 T

Angle between wire and the magnetic field, \theta=30^{\circ}

Current in the wire, I = 2.9 A

We need to find the magnitude of the force on the wire. The magnetic force in the wire is given by :

F=BIL\ \sin\theta\\\\F=0.37\ T\times 2.9\ A\times 5\ m\times \ \sin(30)\\\\F=2.68\ N

So, the magnitude of the force on the wire is 2.68 N. Hence, this is the required solution.

7 0
3 years ago
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