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vovikov84 [41]
3 years ago
5

What element has only two half-filled orbitals in the 3d sublevel?

Chemistry
2 answers:
xenn [34]3 years ago
7 0
It’s either Nickel or Titanium.
Ti ends in 3d2, 2 1/2filled d orbitals
Ni ends in 3d8, with the last 2 d orbitals being 1/2 filled
Ge and Si have full d orbitals
azamat3 years ago
4 0

I'm not sure, but I think its Vandium.


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→
marin [14]

Answer:

[A]²

Explanation:

Since the formation is independent of D, D is 0 order.

Since a quadruples when it is doubled it can be written as

2A^X= 4

To find the unknown power we can assume A= 1 to make the math simple. So When a = 2 (Because you doubled it) raised to X power it will equal 4

so the unknown power is 2

Making the rate law

[a]²[b]⁰

or simply just

[A]²

8 0
3 years ago
The sun's inner core is the hottest part of the sun<br><br> true or false
harkovskaia [24]
False heat rises upwards therefore the hottest part of the sun would be upwards
3 0
3 years ago
Read 2 more answers
If you subtract an objects starting velocity from its final velocity and divide by the time it took to change velocity, what are
amid [387]
Change in velocity over time is acceleration. 

You're finding acceleration . 
7 0
3 years ago
zn (s) 2 hcl (aq) -----&gt; zncl2 (aq) h2(g) if 520 ml of h2 is collected over water at 28oc and the atmospheric pressure is 1.0
nadya68 [22]

The Zn that is 1.33 g is used at the start of the reaction where f is 520 ml and h2 collected over water is 28oc and the atmospheric pressure is 1.0 atm.

Given If 520 ml of H2 is gathered over Wate at 28 diploma Celsius and the atmospheric strain is 1 ATM if vapour strain of wate at 28 diploma celsius is 28.three mmhg then the quantity of zn in grams taken at begin of the response is.

We recognise that

h * 2 = PT - P * h * 20 = 1atm - 0.037atm

= 0.963 atm

1 * h * 2 = Ph * 2V / R * T

= 0.963 atm x 0.520 L / 0.0821 L atm/

molK * 301

= 0.02 mol h2

= 0.02molZn

So 0.02 mol Zn x 65.39 g/mol

= 1.33 g Zn

Read more about zinc;

brainly.com/question/28880469

#SPJ4

3 0
1 year ago
What is the minimum (non-zero) thickness of a benzene (n = 1.501) thin film that will result in constructive interference when v
ad-work [718]

Explanation:

At each reflecting surface (benzene and glass) there will be 180 degree phase change.

Now, for constructive interference the optical path in benzene is \lambda.

Formula to calculate thickness of a benzene thin film is as follows.

     Optical path length through benzene (\lambda) = 2 \times n \times d

Hence, substituting the given values into the above formula as follows.

    Optical path length through benzene = 2 \times n \times d

                   d = \frac{\text{Optical path length through benzene}}{2 \times n}

                       = \frac{\lambda}{2 \times n}  

                       = \frac{615 \times 10^{-9}}{2 \times 1.501}   (as 1 nm = 10^{-9}m

                       = 204.9 m          

Thus, we can conclude that minimum thickness of benzene is 204.9 m.

4 0
3 years ago
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