After reading this whole question, I feel like I've already 
earned 5 points !
-- Two satellites at the same distance, different masses:
The forces of gravity between two objects are directly 
proportional to the product of the objects' masses.  In 
other words, the gravitational forces between the Earth 
and an object on its surface are proportional to the mass of 
the object.  In other words, people with more mass weigh more
on the Earth, and the Earth weighs more on them.  
If the satellites are both at the same distance from Earth, 
then the Earth pulls on the one with more mass with greater 
force, and also the one with more mass pulls on the Earth 
with greater force.
-- Two satellites with the same mass, at different distances:
The forces of gravity between two objects are inversely 
proportional to the square of the distance between them.  
In other words, the gravitational
forces between the Earth 
and an object are inversely proportional
to the square of
the distance between the object and the center of the Earth.  
If
the satellites both have the same mass, then the Earth
pulls on the nearer one with greater force, and also the 
nearer one pulls on the Earth with greater force.
-- Resistor in a circuit when the voltage changes:
The resistance depends on how the resistor was manufactured.  
Its resistance is marked on it, and doesn't change.  It remains 
the same whether the voltage changes, the current changes, 
the time of day changes, the cost of oil changes, etc.
If you increase the voltage in the circuit where that resistor is 
installed, the current through the resistor increases.  If the current 
remains constant, then you can be sure that somebody snuck over 
to your circuit when you weren't looking, and they either installed 
another resistor in series with the original one to make the total 
resistance bigger, or else they snipped the original one out of the 
circuit and quickly connected one with more resistance in its place.
        
             
        
        
        
Answer:
The mass of the ice block is equal to 70.15 kg
Explanation:
The data for this exercise are as follows:
F=90 N
insignificant friction force
x=13 m
t=4.5 s
m=?
applying the equation of rectilinear motion we have:
x = xo + vot + at^2/2
where xo = initial distance =0
vo=initial velocity = 0
a is the acceleration
therefore the equation is:
x = at^2/2
Clearing a:
a=2x/t^2=(2x13)/(4.5^2)=1.283 m/s^2
we use Newton's second law to calculate the mass of the ice block:
F=ma
m=F/a = 90/1.283=70.15 kg
 
        
                    
             
        
        
        
Answer: 
Point 3
Explanation:
It is a summer month position but it has no sunlight.
 
        
             
        
        
        
Answer:
0-4 acceleration comes at 12 m/s where (B) stagnates at 12 m/s and remains for 4 seconds (C) is breaks being activated slowing the car to 6 m/s in 2 seconds and (D) over the course of 4 seconds brings the car to 10 m/s. 
Explanation:
 
        
                    
             
        
        
        
Answer:
 (d) A strong electron-phonon interaction
Explanation:
Superconductivity -
The phenomenon of superconductivity is due to the attractive force between electrons from the exchange of the phonons that cause the bound pair of electrons known as cooper pairs . 
A strong electron -phonon intercation is suitable condition for superconductivity and high resistance .