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laila [671]
3 years ago
7

What is the period that corresponds to a frequency of 39.5 Hz? Answer in units of s.

Physics
1 answer:
tatiyna3 years ago
5 0

The answer for the following problem is mentioned below.

  • <u><em>Therefore the time period is 0.02 seconds.</em></u>

Explanation:

Frequency:

The number of waves that pass a fixed place in a given amount of time. (or)

The number of waves that pas by per second.

The SI unit of the frequency is Hertz(Hz).

Time period:

The time taken for one complete cycle of vibration to pass a given point.

The SI unit of time period is seconds. (s)

Given:

Frequency (f) = 39.5 Hz

To calculate:

Time period (T)

We know;

According to the problem;

From the problem;

<u>f = </u>\frac{1}{T}<u></u>

Where;

f represents the frequency

T represents the time period

 f = \frac{1}{39.5}

 f = 0.02 seconds

<u><em>Therefore the time period is 0.02 seconds.</em></u>

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A race car traveling at 10. meters per second accelerates at the rate of 1.5 meters per seconds while traveling a distance of 7,
Arturiano [62]

The final speed of the car is 2) 150 m/s

Explanation:

Since the motion of the car is a uniformly accelerated motion, we can solve the problem by using the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For the car in this problem, we have

u = 10 m/s

a=1.5 m/s^2

s = 7,467 m

Solving for v, we find the final velocity (and speed) of the car:

v=\sqrt{u^2+2as}=\sqrt{10^2+2(1.5)(7,467)}=150 m/s

Learn more about accelerated motion:

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4 0
3 years ago
Read 2 more answers
A ferris wheel is 35 meters in diameter and boarded from a platform that is 2 meters above the ground. The six o'clock position
Drupady [299]

Answer:

h=f(t)= -17.5cos(\pi /3)+20.5

Explanation:

Amplitude is 35/2=17.5

Midline= Distance from ground + Amplitude = 17.5+3= 20.5

Period is time taken to finish 6 minutes

2π/b=T

2π/b=6

b=π/3

h=f(t)= -17.5cos(\pi /3)+20.5

6 0
3 years ago
Read 2 more answers
What kind of wave (transverse of longitudinal) is each of the following and why?
Elina [12.6K]

Answer:

1.) Longitudinal waves

2.) Transverse waves

3.) Longitudinal waves

Explanation:

The sound of one whale calling another whale underwater.  is a longitudinal wave since the medium, in this case the body of water, is vibrating parallel to the direction of propagation of the wave.

A pulse sent down a stretched rope by snapping one end of it. ( transverse wave) because its oscillations are perpendicular to the direction of the wave or path of propagation

The vibrations in a guitar string

Longitudinal wave. Because its oscillations are parallel to the direction of the wave or path of propagation

5 0
3 years ago
A magnetic field is applied to a freely floating uniform iron sphere with radius R = 2.00 mm. The sphere initially had no net ma
grigory [225]

Answer:

\omega=4.2704*10^-^5 rad/s

Explanation:

Angular Momentum Formula For atoms=L_{atom}=0.12Nm_{s}h

Where:

m_{s}h is the momentum for one atom (m_s is the spin quantum number)

N is the number of atoms=\frac{N_{A}*m}{M}

Where:

N_A is Avogadro Number

m is the mass of sphere

M is the molar mass of iron

Angular Momentum Formula For atoms will be=L_{atom}=0.12\frac{N_{A}m}{M} m_{s}h

Angular Momentum of Sphere=L_{sphere}=I\omega

where:

I=\frac{2mR^{2}}{5}

So,Angular Momentum of Sphere=L_{sphere}=\frac{2mR^{2}}{5}\omega

Angular Momentum of sphere=Angular Momentum of atoms

L_{sphere}=L_{atom}

\frac{2mR^{2}}{5}\omega=0.12\frac{N_{A}m}{M} m_{s}h

For iron, m_s =\frac{1}{2}. So above equation will become:

\omega=\frac{0.12*5*N_{A}h}{4*M*R^{2} }

Where R=2mm, M=0.0558Kg/mol (Molar Mass of iron),h=Planck's Constant/2π

\omega=\frac{0.12*5*(6.022*10^{23})(6.63*10^{-34}/2*\pi)}{4*0.0558*(2*10^{-3})^{2}}

\omega=4.2704*10^-^5 rad/s

5 0
3 years ago
If the mass of a body is 9.8kg on the earth, what would be its mass on the moon?​
devlian [24]

Answer:

it will remain same because mass of the body is constant everywhere

4 0
2 years ago
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