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3 years ago

What is the period that corresponds to a frequency of 39.5 Hz? Answer in units of s.

Physics

1 answer:

tatiyna3 years ago

5 0

The answer for the following problem is mentioned below.

Therefore the time period is 0.02 seconds.

Explanation:

Frequency:

The number of waves that pass a fixed place in a given amount of time. (or)

The number of waves that pas by per second.

The SI unit of the frequency is Hertz(Hz).

Time period:

The time taken for one complete cycle of vibration to pass a given point.

The SI unit of time period is seconds. (s)

Given:

Frequency (f) = 39.5 Hz

To calculate:

Time period (T)

We know;

According to the problem;

From the problem;

f = $\frac{1}{T}$

Where;

f represents the frequency

T represents the time period

f = $\frac{1}{39.5}$

f = 0.02 seconds

Therefore the time period is 0.02 seconds.

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The diagram below shows the heating of an unknown substance (it is not water). Its melting point is? The diagram below shows the

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Answer:

the answer is B

Melting point, temperature at which the solid and liquid forms of a pure substance can exist in equilibrium. As heat is applied to a solid, its temperature will increase until the melting point is reached. More heat then will convert the solid into a liquid with no temperature change.

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2 years ago

Mrs. Rohaley gives you a piece of iron and asks you to determine the physical and chemical properties of the metal. She wants yo

Fofino [41]

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3 years ago

1/012=1/0.05+1/d' hiiiiiiiiii

klasskru [66]

Correct question is;

1/0.12 = (1/0.05) + (1/d')

Answer:

d' = -1/700

Explanation:

1/0.12 = (1/0.05) + (1/d')

Let's rearrange to get;

(1/d') = (1/0.12) - (1/0.05)

(1/d') = (1/(12/100)) - (1/(5/100))

(1/d') = 100/12 - 100/5

Let's multiply through by 60 to get rid of the denominators on the right side;

> (1/d') = 500 - 1200

> (1/d') = -700

> d' = -1/700

8 0

2 years ago

A wheel of mass 4kg is pulled up a plane inclined at 30° to the horizontal by a force of 45N applied to the axle and parallel to

Len [333]

Answer:

v = 10 m/s

Explanation:

Let's assume the wheel does not slip as it accelerates.

Energy theory is more straightforward than kinematics in my opinion.

Work done on the wheel

W = Fd = 45(12) = 540 J

Some is converted to potential energy

PE = mgh = 4(9.8)12sin30 = 235.2 J

As there is no friction mentioned, the remainder is kinetic energy

KE = 540 - 235.2 = 304.8 J

KE = ½mv² + ½Iω²

ω = v/R

KE = ½mv² + ½I(v/R)² = ½(m + I/R²)v²

v = √(2KE / (m + I/R²))

v = √(2(304.8) / (4 + 0.5/0.5²)) = √101.6

v = 10.07968...

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2 years ago

An amateur astronomer grinds a double convex lens whose surfaces have radii of curvature of 40 cm and 60 cm. The glass has an in

DedPeter [7]

Answer:

44.4cm

Explanation:

glass has an index of refraction .n = 1.54

radii of curvature of 40 cm R1 = 40 by

radii of curvature of 600 cm R2 = 60

Now, by lens maker formula

1/f = (n - 1) (1/R1 - 1/R2)

Putting in the given values for n = 1.54 , we get f = 22.2

$\frac{1}{f} = (1.54 -1) (\frac{1}{40cm} -\frac{1}{(-60cm)} )$

$\frac{1}{f} = 0.0225$

f = 1 / 0.0225

f = 44.4cm

so, focal length in air will be = 44.4 cm

6 0

2 years ago