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3 years ago

If the reservoir is 190 metres above the intake, how many cubic metres of water will there be delivered during the night?

1 answer:

5 0

This looks like a part of a full question. We need to know the acceleration due to gravity, water density, the power of the water or speed at which it flows to the reservoir. We also need to know the diameter of the pipe, the number of hours we are considering in this question because you mentioned the it will be delivered at night.

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dalvyx [7]

Answer:

Step-by-step explanation:

Based on the order of operations, this would be 3 times 3, which is 9 I think.

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3 years ago

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What is the 69th term of -13,-33,-53

baherus [9]

Answer:

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Step-by-step explanation:

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3 years ago

Solve this equation for x: 2x^2 + 12x - 7 = 0

zhannawk [14.2K]

Answer:

x=0.5355 or x=-6.5355

First step is to: Isolate the constant term by adding 7 to both sides

Step-by-step explanation:

We want to solve this equation: $2x^2 + 12x - 7 = 0$

On observation, the trinomial is not factorizable so we use the Completing the square method.

Step 1: Isolate the constant term by adding 7 to both sides

$2x^2 + 12x - 7+7 = 0+7\\2x^2 + 12x=7$

Step 2: Divide the equation all through by the coefficient of $x^2$ which is 2.

$x^2 + 6x=\frac{7}{2}$

Step 3: Divide the coefficient of x by 2, square it and add it to both sides.

Coefficient of x=6

Divided by 2=3

Square of 3= $3^2$

Therefore, we have:

$x^2 + 6x+3^2=\frac{7}{2}+3^2$

Step 4: Write the Left Hand side in the form $(x+k)^2$

$(x+3)^2=\frac{7}{2}+3^2\\(x+3)^2=12.5\\$

Step 5: Take the square root of both sides and solve for x

$x+3=\pm\sqrt{12.5}\\x=-3\pm \sqrt{12.5}\\x=-3+ \sqrt{12.5}, $ or $x= -3- \sqrt{12.5}\\$x=0.5355 or x=-6.5355$

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3 years ago

What is the circumference of a circular disc with a diameter of 10 centimeters? (Round your answer to the nearest tenth.)

Evgen [1.6K]

To determine what the circumference is simply take the value of the diameter and multiply it to the value of Pi or 3.141....

C = Pi • d
C = (3.14)(10 cm)
C = 31.41 cm or 31.4 cm, rounded to the nearest tenth.

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3 years ago

What is vertical asymptote for the given equation f(x) = log(x - 5) + 2

Ierofanga [76]

The answer is:
X = 5

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3 years ago