The mass of sodium sulfite that was used will be 1,890 grams.
<h3>Stoichiometric problems</h3>
First, the equation of the reaction:
The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.
Mole of 960 grams SO2 = 960/64 = 15 moles
Equivalent mole of sodium sulfite that reacted = 15 moles
Mass of 15 moles sodium sulfite = 15 x 126 = 1,890 grams
More on stoichiometric problems can be found here: brainly.com/question/14465605
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Answer:
Generally, observed behavior that can be formulated into a statement, sometimes mathematical in nature, is called a natural law- D.
Add more solute..............
Answer:
There are
1.479
×
10
−
13
concentration of hydrogen ions
m
o
l
L
.
Explanation:
Because pH is a logarthmic scale, we can use the formula:
[
H
+
]
=
10
-pH
. Where...
=>
[
H
+
]
is the concentration of hydrogen ions in the solution.
=>
p
H
is the pH of the solution.
=> Where
10
is the base of the power - it's a logarithm formula.
We can now just sub in the values and solve for [
H
+
]
.
[
H
+
]
=
10
-pH
=
10
−
(
12.83
)
=
1.479108388
×
10
−
13
We can round (if required) to
1.479
×
10
−
13
.
Thus, there are
1.479
×
10
−
13
concentration of hydrogen ions
m
o
l
L
.
Hope this helps :)
Answer:
A liquid has a definite volume but not a definite shape
