What is the capillary rise of ethanol in a glass tube with a 0.1 mm radius if the surface tension of ethanol is 0.032Jm2 and the
1 answer:
Answer: The capillary rise(h) in the glass tube is = 0.009m
Explanation:
Using the equation
h = 2Tcosθ/rpg
Given
Contact angle, θ = Zero
h = height of the glass tube=?
T = surface tension =
r = radius of the tube = 0.1mm =0.0001m
p= density of ethanol =
g=
h =
h= 0.09m
Therefore the capillary rise in the tube is 0.09m
You might be interested in
Answer:
The resonance forms of O3 are attached as an image.
Explanation:
A compound with different contributing structures comes together and forms a resonating or intermediate structure that best describes the properties of that compound.
The given compound is ozone, having the chemical formula
O3 = 6 electrons * 3 = 18 electrons
O → prefers to have a complete their octet
The bonding electrons and lone pair electrons are radical electrons that are present on the oxygen atoms tend to delocalize and results in various resonating forms of O3.
<u>Answer:</u>
<u>For 1:</u> The value of for above reaction is 36.83
<u>For 2:</u> The value of for above reaction is 36.83
<u>For 3:</u> The equilibrium partial pressure of Indium is 0.126 atm
<u>For 4:</u> The equilibrium partial pressure of hydrogen gas is 0.094 atm
<u>For 5:</u> The equilibrium partial pressure of Indium dihydrogen is 0.018 atm
<u>Explanation:</u>
We are given:
Partial pressure of Indium gas = 0.0650 atm
Partial pressure of hydrogen gas = 0.0330 atm
Partial pressure of Indium dihydride = 0.0790 atm
The given chemical equation follows:
<u>Initial:</u> 0.065 0.033 0.079
<u>At eqllm:</u> 0.065-x 0.033-x 0.079+x
- <u>For 1:</u>
The expression of for above reaction follows:
Putting values in above equation, we get:
Hence, the value of for above reaction is 36.83
- <u>For 2:</u>
We are given:
of the reaction = 1.48
There are 3 conditions:
- When
; the reaction is product favored.
- When
; the reaction is reactant favored.
- When
; the reaction is in equilibrium.
As, for the given reaction, the reaction is reactant favored.
Hence, the reaction proceed in the backward direction to attain equilibrium
- <u>For 3:</u>
The expression of for above reaction follows:
Putting values in above equation, we get:
Neglecting the value of x = 0.835 because the reaction is going backwards. So, by taking this value, the pressure of the reactants will decrease
So, equilibrium partial pressure of Indium = (0.065 - x) = [0.065 - (-0.061)] = 0.126 atm
- <u>For 4:</u>
The equilibrium partial pressure of hydrogen gas = (0.033 - x) = [0.033 - (-0.061)] = 0.094 atm
- <u>For 5:</u>
The equilibrium partial pressure of Indium dihydrogen = (0.079 + x) = [0.079 + (-0.061)] = 0.018 atm