Ca + 2HCl = CaCl₂ + H₂

m(Ca)=60 g

c=1.25 mol/l

M(Ca)=40g/mol

v-?

m(Ca)/M(Ca)=m(HCl)/[2M(HCl)]=n(HCl)/2

n(HCl)=2m(Ca)/M(Ca)

n(HCl)=cv

cv=2m(Ca)/M(Ca)

v=2m(Ca)/{cM(Ca)}

v=2·60g/mol/{1.25mol/l·40g/mol}=2.4 l = 2400 ml

2400 milliliters of a 1.25 molar HCl solution would be needed

**Answer:**

**The amount of water vapor in a given volume of air is humidity.The amount of water vapor in the air at any one time depends on temperature . Warmer air holds more water than cooler air. Clouds form when humidity is low and thetemperature is high . Relative humidity is defined as the amount of water vapor in the air divided by the amount that would have to be present in the same air to form a cloud or condense on a surface. Dew is related to the humidity of the previous day. The air temperature at which water vapor in the air condenses onto cool surfaces is the dew point.**

**Explanation:**

**Answer:**

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

**Explanation:**

**Given data:**

Initial volume of gas = 5.00 L

Initial temperature = 0°C (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

**Solution:**

**Formula:**

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

**Conversion of mL into L.**

Final volume = 1100 mL/1000 = 1.1 L

Final volume = 87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

**
**60.06 K - 273 = -213.09°C

**2)**

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

**3)**

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

**Answer:**

"1.
buoyant or suspended in water or air.

2.not settled in a definite place; fluctuating or variable."

**Explanation:**

Hope this helps! :)

**Answer : The for this reaction is, -88780 J/mole.**

**Solution :**

**The balanced cell reaction will be, **

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

**The half oxidation-reduction reaction will be :**

**Oxidation :**

**Reduction :**

**Now we have to calculate the Gibbs free energy.**

**Formula used :**

where,

= Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

= standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

**Therefore, the for this reaction is, -88780 J/mole.**