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Fynjy0 [20]
3 years ago
9

enmoles of helium gas and one mole of solid argon are in thermal equilibrium with each other at 10 K. Both helium and argon are

monatomic, and argon is ten times as massive as helium. How do the average speeds of the atoms in these two substances compare under the conditions specified
Chemistry
1 answer:
oksian1 [2.3K]3 years ago
3 0

Answer:

Average speed of helium is higher than argon.

Explanation:

The average speed of helium is higher than argon atom under the conditions specified because of lower mass of the helium atom as compared to argon atom. Average speed of an atom is inversely proportional to mass of the atom. If mass of an atom decreases, the atom moves with higher speed while on the other hand, if the mass of an atom increases the average speed of an atom decreases.

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What are the flocculation basins?
Mila [183]

Answer:

flocculation is the operation in which the coagulated water must be gently mixed at a propeller speed of 15 to 20 rpm to promote the growth of the floc. ... The flocculation basin often has a number of compartments with decreasing mixing speeds as the water advances through the basin.

Explanation:

8 0
3 years ago
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After decaying for 48 hours, one-sixteenth (1/16) of the original mass of a radioisotope sample remains unchanged. What is the h
Hunter-Best [27]

The half-life of this radioisotope : 12 hr

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

Usually radioactive elements have an unstable atomic nucleus.  

General formulas used in decay:  

\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

t = duration of decay  

t 1/2 = half-life  

N₀ = the number of initial radioactive atoms  

Nt = the number of radioactive atoms left after decaying during T time  

t=48 hr

\tt \dfrac{Nt}{No}=\dfrac{1}{16}

The half-life :

\tt \dfrac{1}{16}=\dfrac{1}{2}^{(48/t\frac{1}{2} )}\\\\(\dfrac{1}{2})^4=(\dfrac{1}{2})^{48/t\frac{1}{2}}\\\\4=48/t\frac{1}{2}\\\\t\frac{1}{2}=12~hr

7 0
3 years ago
HURRY!!!! TIMED!!! WILL GIVE BRAINLIST!!!
aev [14]

Explanation:

(a) write a balanced equation for the reaction

CaCO3 + HCl --> CaCl2 + H2O + CO2

The balanced equation is given as;

CaCO3 + 2HCl → CaCl2 + H2O + CO2  

(b) when the reaction was complete, 800 mL of carbon dioxide gas was collected. How many moles of calcium carbonate were used in the creation?

From the balanced reaction;

1 mol of CaCO3 reacts to produce 1 mol of CO2

1 mol of CO2 = 22.4 L of CO2

This means;

1 mol of CaCO3 reacts to produce 22.4L  of CO2

x mol would produce 800ml (0.8 L) of CO2

1 = 22.4

x = 0.8

x = 0.8 * 1 / 22.4 = 0.0357 mol

(c) How many grams of CaCO3 were used?

Mass = Number of moles * Molar mass

Molar mass of CaCO3 = 100.0869 g/mol

Mass = 0.0357 mol * 100.0869 g/mol = 3.57 g

(d) If there was another contaminant in the sample that was not un reactive, would this have caused the percent yield of carbon dioxide to be higher, lower, or the same, explain your answer.

The same

An un reactive contaminant in the sample is most likely a catalyst. Catalysts only affect the rate of reaction. They do not affect yields of products.

7 0
3 years ago
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