Newton’s third law of motion is also known as action/_______?
2 answers:
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To increase the centripetal acceleration to , you can double the speed or decrease the radius by 1/4
Explanation:
An object is said to be in uniform circular motion when it is moving at a constant speed in a circular path.
The acceleration of an object in uniform circular motion is called centripetal acceleration, and it is given by
where
v is the speed of the object
r is the radius of the circular path
In the problem, the original centripetal acceleration is
We want to increase it by a factor of 4, i.e. to
We notice that the centripetal acceleration is proportional to the square of the speed and inversely proportional to the radius, so we can do as follows:
- We can double the speed:
v' = 2v
This way, the new acceleration is
so, 4 times the original acceleration
- We can decrease the radius to 1/4 of its original value:
So the new acceleration is
so, the acceleration has increased by a factor 4 again.
Learn more about centripetal acceleration:
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Answer:
n = 756.25 giga electrons
Explanation:
It is given that,
If the charge on the negative plate of the capacitor,
Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :
e is the charge on electron
or
n = 756.25 giga electrons
So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.
Answer:
The temperature of the core raises by every second.
Explanation:
Since the average specific heat of the reactor core is 0.3349 kJ/kgC
It means that we require 0.3349 kJ of heat to raise the temperature of 1 kg of core material by 1 degree Celsius
Thus reactor core whose mass is will require
energy to raise it's temperature by 1 degree Celsius in 1 second
Hence by the concept of proportionately we can infer 150 MW of power will increase the temperature by
Answer:
(a) The magnetic energy density in the field is 6.366 J/m³
(b) The energy stored in the magnetic field within the solenoid is 5 kJ
Explanation:
magnitude of magnetic field inside solenoid, B = 4 T
inner diameter of solenoid, d = 6.2 cm
inner radius of the solenoid, r = 3.1 cm = 0.031 m
length of solenoid, L = 26 cm = 0.26 m
(a) The magnetic energy density in the field is given by;
(b) The energy stored in the magnetic field within the solenoid