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Sever21 [200]
3 years ago
6

) A concentration cell is based on the aqueous reaction

Chemistry
1 answer:
Brrunno [24]3 years ago
8 0

Answer:

Kindly check the attachment for the diagram representing the cell and showing all necessary components including: anode, cathode, electron flow, cation flow and anion flow.

Explanation:

So, the reaction in the concentration cell is given below as;

Cu2+(1.00 M) → Cu2+(0.0100 M).--(1).

The anode = Cu2+(0.0100 M) because it has lesser Concentration, thus, lesser potential value.

Cathode = Cu2+(1.00 M) because it has higher Concentration, hence higher potential value.

It must be noted that in the digaram depicting the Reaction, the electrons moves from the anode part of the cell to the cathode part of the cell and this is done through an external circuit. The following are the things that happens at each electrode;

At the Anode: in here is where oxidation occurs and Cu^2+ is released into the solution.

At the cathode: in here is where the reduction occur and the Cu^2+ moves in the direction to where the Cu electrode is, thus, causing the deposition of Cu.

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Answer:

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Number of moles, n, of hydrogen gas H₂ is given by the relation;

n = \dfrac{Mass \ of \ hydrogen \ gas, \, H_2 }{Molar \ mass \ of  \, H_2 } = \dfrac{2.23}{2.016} = 1.106 \ moles

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Given that one mole of H₂ reacts with one mole of Br₂ to produce two moles of HBr

1.106 mole of H₂ will react with 1.106 mole of Br₂ to produce 2 × 1.106 which is 2.212 moles of HBr

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The mass of HBr produced = 80.91 × 2.212 = 178.997 g ≈ 179 grams

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