Hydrogen gas is harmless to your feet so since you don’t need protection against it that seems the best answer.
Answer: 75V
Explanation:
Given that,
total resistance (Rtotal) = 150Ω
Current (I) = 0.5A
Change in electric potential (V) = ?
Recall that potential difference is the product of amount of current and the amount of resistance in the circuit. And its unit is volts.
So, apply the formula V = I x Rtotal
V = 0.5A x 150Ω
V = 75V
Thus, the change in electric potential across the circuit is 75 Volts
Based on the length of side of the cube given, the length of the needle is 2.28 inches.
<h3>What is the length of the needle?</h3>
The length of the side of a cube and its diagonal are related by the formula below:

where s is length of side



Therefore, the length of the needle is 2.28 inches
Learn more about length of diagonal of cube at: brainly.com/question/800212
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Answer:
Velocity = 0.4762 m/s
Explanation:
Given the details for the simple harmonic motion from the question as:
Angular frequency, ω = 12 rad/s
Amplitude, A = 0.060 m
Displacement, y = 0.045 m
The initial Energy = U = (1/2) kA²
where A is the amplitude and k is the spring constant.
The final energy is potential and kinetic energy
K + U = (1/2) mv² + (1/2) kx²
where x is the displacement
m is the mass of the object
v is the speed of the object
Since energy is conservative. So, the final and initial energies are equal as:
(1/2) k A² = (1/2) m v² + (1/2) kx²
Using, ω² = k/m, we get:
Velocity:
![v=\omega\times \sqrt{[ A^2 - y^2 ]}](https://tex.z-dn.net/?f=v%3D%5Comega%5Ctimes%20%5Csqrt%7B%5B%20A%5E2%20-%20y%5E2%20%5D%7D)
![v=\omega\times \sqrt{[ {0.06}^2 - {0.045}^2 ]}](https://tex.z-dn.net/?f=v%3D%5Comega%5Ctimes%20%5Csqrt%7B%5B%20%7B0.06%7D%5E2%20-%20%7B0.045%7D%5E2%20%5D%7D)
<u>Velocity = 0.4762 m/s</u>
Answer:
the correct affirmation is the 3
Explanation:
Let's analyze the problem with Newton's second law before looking at the claims.
X axis parallel to the plane, positive down
F -fr + Wₓ = ma
Y Axis perpendicular to the plane
N -Wy = 0
With trigonometry
Wₓ = W sin θ
Wy = w cos θ
Let's multiply by the displacement along the plane, to relate to the work, which has as expression W = F d
F d -fr d + Wx d = ma d
Push W₁ = Fd
frictional force W₂ = -fr d
gravity W₃ = Wx d
W₁ + W₃ -W₂ = m a d
Analysis affirmations:
R1) false. The work of gravity is the subtraction
R2) false. Each force contributes according to its magnitude
R3) true. In the equation we see that, if the acceleration is zero, W2 = W1 + W3
R4) False. It equals the difference
the correct affirmation is the 3