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nordsb [41]
3 years ago
12

Can someone help ? I need help please

Physics
2 answers:
Tju [1.3M]3 years ago
8 0

Answer: B  S=D/T

Explanation:

smarty

MAXImum [283]3 years ago
5 0

Answer:

B

Explanation:

to see how fast she is going per second, you would have to divide the distance traveled by the seconds it took to travel the distance

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If Joey ran 60 meters in 10 seconds, then his velocity is ________ m/s.
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Answer:

6 m/s

Explanation:

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4 years ago
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Two sound waves (speed 343 m/s) have different wavelengths. The first has a wavelength of 5.72 m, and the second a wavelength of
lys-0071 [83]

Answer:

The beat frequency is 30 Hz

Explanation:

Given;

velocity of the two sound waves, v = 343 m/s

wavelength of the first wave, λ₁ = 5.72 m

wavelength of the second wave, λ₂ = 11.44 m

The frequency of the first wave is calculated as follows;

F₁ = v/λ₁

F₁ = 343 / 5.72

F₁ = 59.97 HZ

The frequency of the second wave is calculated as follows;

F₂ = v/λ₂

F₂ = 343 / 11.44

F₂ = 29.98 Hz

The beat frequency is calculated as;

Fb = F₁ - F₂

Fb =  59.97 HZ - 29.98 Hz

Fb = 30 Hz

6 0
3 years ago
Which among the following statements is correct?
Vinvika [58]

Answer:

C

Explanation:

Velocity is just speed with direction

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3 years ago
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Which statement correctly describes the electrons in a water molecule?. . A.Which statement correctly describes the electrons in
exis [7]

The statement “Electrons are pulled closer to the oxygen atom” correctly describes the electrons in a water molecule. The correct answer between all the choices given is the second choice or letter B. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

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What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of – 30.0 nC?
Nastasia [14]

Answer:

F=1.26*10^{-3}N

Explanation:

Assuming the pith balls as point charges, we can calculate the repulsive force between them, using Coulomb's law:

F=\frac{kq_1q_2}{d^2}

We observe that the magnitude of the electric force is directly proportional to the product of the magnitude of both signed charges(q_1,q_2) and inversely proportional to the square of the distance(d) that separates them.

Replacing the given values, where k is the Coulomb constant:

F=\frac{8.99*10^{9}\frac{N\cdot m^2}{C^2}(-30*10^{-9}C)(-30*10^{-9}C)}{(8*10^{-2}m)^2}\\F=1.26*10^{-3}N

8 0
3 years ago
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