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3 years ago

PLEASE ANSWER ASAP

1 answer:

8 0

Its an inelastic collision because the force from the bat causes it to bounce back. It is also an elastic force because catching the ball call for the energy of the ball to be deformed and restored into the mitt.

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Most sulfide compounds of the transition metals are insoluble in water. Many of these metal sulfides have striking and character

docker41 [41]

Answer:

$Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)$

$2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)$

$Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)$

Explanation:

We're given the following ions:

$Fe^{2+}, Cr^{3+}, Ni^{2+}$

Hydrogen sulfide is a weak acid, so it only ionizes to ions to a very low extent. This means we would expect to see it in a molecular form in a net ionic equation rather than a dissociated form (hydrogen cations and sulfide anions). In each of these net ionic equations, we expect the three cations to displace hydrogen from hydrogen sulfide and form three precipitates.

Firstly, iron(II) displaces hydrogen forming iron(II) sulfide and acidic conditions:

$Fe^{2+}(aq)+H_2S(aq)\rightarrow FeS (s)+2H^+ (aq)$

Secondly, chromium(III) cation displaces hydrogen forming chromium(III) sulfide:

$2Cr^{3+}(aq)+3H_2S(aq)\rightarrow Cr_2S_3 (s)+6H^+ (aq)$

Thirdly, nickel(II) cation displaces hydrogen forming nickel sulfide:

$Ni^{2+}(aq)+H_2S(aq)\rightarrow NiS (s)+2H^+ (aq)$

7 0

3 years ago

A chunk of tin weighing 18.5 grams and originally at 97.38 °C is dropped into an insulated cup containing 75.7 grams of water at

balandron [24]

Answer:

The final temperature of the water is 22.44°C.

Explanation:

Heat lost by tin will be equal to heat gained by the water

$-q_1=q_2$

Mass of tin = $m_1=18.5 g$

Specific heat capacity of tin = $c_1=0.21 J/g^oC$

Initial temperature of the tin = $T_1=97.38^oC$

Final temperature = $T_2$ =T

$q_1=m_1c_1\times (T-T_1)$

Mass of water= $m_2=75.7 g$

Specific heat capacity of water= $c_2=4.184 J/g^oC$

Initial temperature of the water = $T_3=21.52^oC$

Final temperature of water = $T_2$ =T

$q_2=m_2c_2\times (T-T_3)$

$-q_1=q_2$ (Law of Conservation of energy)

$-(m_1\times c_1\times (T-T_1))=m_2\times c_2\times (T-T_3)$

On substituting all values:

$-(18.5 g\times 0.21 J/g^oC\times (T-97.38^oC))=75.7 g\times 4.184 J/g^oC\times (T-21.52 ^oC)$

we get, T = 22.44°C

The final temperature of the water is 22.44°C.

3 0

3 years ago

How many molecules are in 2.10 mol co2 ??

Mashutka [201]

4.5x10^22.
How many molecules are in 2.10 mol CO2? 1.26x10^24 molecules.
What is the molar mass of AuCl3?

6 0

3 years ago

Read 2 more answers

Methylation is a process that involves which of the following metals

Vesnalui [34]

Methylation is a process that involves Mercury metal. Methylation is a process by which a methyl groups are added to the DNA molecule. when it occurs it can change the activity of a DNA segment without changing the sequence, additionally, when located in a gene promoter it may act to repress gene transcription.

7 0

4 years ago

Which of the following solutions contains the largest number of moles of dissolved particles? a.) 25 ml of sodium chloride b.) 2

kirza4 [7]

Answer:

b.) 25 ml of aluminum hydroxide

Explanation:

For this question, we have to assume that we have the same concentration for all the solutions, for example, 1 M. Additionally, we have to take into account the ionization reaction for each species:

a) $NaCl~->~Na^+~+~Cl^-$ we have to ions

b) $Al(OH)_3~->~Al^+^3~+~3OH^-$ we have fourth ions

c) $CH_3COOH~->~CH_3COO^-~+~H^+$ we have two ions

d) $C_6H_1_2O_6~->~C_6H_1_2O_6$ we have one ion

If we have the same volume and the same concentration the variables that will help us to answer the question would be the number of ions. If we have more ions we will have more particles dissolved. Therefore the answer would be b) (due to the fourth ions).

I hope it helps

5 0

3 years ago

Read 2 more answers