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Semmy [17]
1 year ago
6

Morphine sulfate given intravenously, by itself, at once, is known as:__________a. none of the answers are correct b. iv push c.

iv piggyback d. continuous infusion
Chemistry
1 answer:
Travka [436]1 year ago
6 0

Morphine sulfate given intravenously, by itself, at once, is known as push.

<h3>What is Morphine ?</h3>

A member of the opiate family of painkillers, morphine is naturally present in opium, a dark-brown substance found in poppies (Papaver somniferum). Morphine can be given orally, sublingually, inhaled, injected into a muscle, injected under the skin, intravenously, into the area around the spinal cord, transdermally, or as a rectal suppository. It causes analgesia and modifies perception and emotional reaction to pain by acting directly on the central nervous system (CNS). With repeated use, tolerance and reliance could develop on both a physical and psychological level. It is widely used for pain from myocardial infarction, kidney stones, and labor pain and can be taken for both acute and chronic pain.

To learn more about  Morphine  from the given link:

brainly.com/question/13558361

#SPJ4

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<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

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We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

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Equation for the second dissociation of sulfuric acid:

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<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

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