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vlada-n [284]
3 years ago
8

If you want to conduct an electrical current, which situation would produce a solution capable of this?

Physics
2 answers:
nataly862011 [7]3 years ago
8 0

Answer:

D.) Dissolving solid NaF in water

Explanation:

Dissolving solid NaF in water will produce an electrical-conducting solution.

Dissolving sugar in water will not since sugar just dissolves but not into ions. Oil is nonpolar so water nor NaBr will dissolve in it

harkovskaia [24]3 years ago
3 0
Replacing electrical cables. Wouldn't it be a matter of knowing what is a suitable conductor in this situation. The solution produced in the situation would be to use a copper wire. 
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A sample of gas is enclosed in a container of fixed volume. Identify which of the following statements are true. Check all that
motikmotik

Answer:

B. If the container is cooled, the gas particles will lose kinetic energy and temperature will decrease.

C. If the gas particles move more quickly, they will collide more frequently with the walls of the container and pressure will increase.

E. If the gas particles move more quickly, they will collide with the walls of the container more often and with more force, and pressure will increase.

#FreeMelvin

7 0
3 years ago
a chuck wagon with an initial velocity of 4 m/s and a mass of 35 kg gets a push with 350 joules of force. what is the wagon's fi
Kitty [74]

Answer:

the final velocity of the wagon is 6 m/s.

Explanation:

Given;

initial velocity of the wagon, u = 4 m/s

mass of the wagon, m = 35 kg

energy applied to the wagon, E = 350 J

The final velocity of the wagon is calculated as;

E = ¹/₂m(v² - u²)

m(v^2-u^2) = 2E\\\\v^2-u^2 = \frac{2E}{m} \\\\v^2 =  \frac{2E}{m}  + u^2\\\\v = \sqrt{\frac{2E}{m}  + u^2} \\\\v = \sqrt{\frac{2(350)}{35}  + (4)^2}\\\\v = 6 \ m/s

Therefore, the final velocity of the wagon is 6 m/s.

8 0
3 years ago
Which force is responsible for allowing carbon-14 to become stable? *
Bas_tet [7]

Answer:weak nuclear

Explanation:

There weak nuclear force is responsible for allowing carbon-14 to become stable

3 0
3 years ago
A constant magnetic field passes through a single rectangular loop whose dimensions are 0.35 m × 0.55 m. The magnetic field has
Pani-rosa [81]

Answer:

Part a)

EMF = 0.38 V

Part b)

\frac{dA}{dt} = 0.43 m^2/s

Explanation:

Part a)

Initial value of magnetic flux is given as

\phi_1 = BAcos\theta

\phi_1 = (2.1)(0.35 \times 0.55) cos65

so we have

\phi_1 = 0.17 Wb

Final flux through the loop is given as

\phi_2 = 0

now EMF is given as

EMF = \frac{\phi_1 - \phi_2}{\Delta t}

EMF = \frac{0.17 - 0}{0.45}

EMF = 0.38 V

Part b)

If magnetic field is constant while Area is changing

So EMF is given as

E = Bcos65 \times \frac{dA}{dt}

0.38 = 2.1 cos65(\frac{dA}{dt})

\frac{dA}{dt} = 0.43 m^2/s

5 0
3 years ago
A football quarterback runs 15.0 m straight down the playing field in 3.00 s. He is then hit and pushed 3.00 m straight backward
algol [13]

Answer:

a) v_{1}=14.29m/s\\v_{2}=9.25m/s\\v_{3}=6.36m/s

b) v=+9.97m/s

Explanation:

From the exercise we know that

x_{1} =15m, t_{1}=3s

x_{2} =-3m, t_{1}=1.74s

x_{3} =29m, t_{3}=5.20s

From dynamics we know that the formula for average velocity is:

v=\frac{x_{2}-x_{1}  }{t_{2}-x_{1}  }

a) For the three intervals:

v_{1}=\frac{x_{2}-x_{1}  }{t_{2}-t_{1}  }=\frac{(-3-15)m}{(1.74-3)s}=14.29m/s

v_{2}=\frac{x_{3}-x_{2}  }{t_{3}-t_{2}  }=\frac{(29-(-3))m}{(5.20-1.74)s}=9.25m/s

v_{3}=\frac{x_{3}-x_{1}  }{t_{3}-t_{1}  }=\frac{(29-15)m}{(5.20-3)s}=6.36m/s

b) The average velocity for the entire motion can be calculate by the following formula:

v=\frac{v_{1}+v_{2}+v_{3}   }{n} =\frac{(14.29+9.25+6.36)m/s}{3}=+9.97m/s

8 0
3 years ago
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