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2 years ago

If you want to conduct an electrical current, which situation would produce a solution capable of this?

Physics

2 answers:

nataly862011 [7]2 years ago

8 0

Answer:

D.) Dissolving solid NaF in water

Explanation:

Dissolving solid NaF in water will produce an electrical-conducting solution.

Dissolving sugar in water will not since sugar just dissolves but not into ions. Oil is nonpolar so water nor NaBr will dissolve in it

harkovskaia [24]2 years ago

3 0

Replacing electrical cables. Wouldn't it be a matter of knowing what is a suitable conductor in this situation. The solution produced in the situation would be to use a copper wire.

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What is the necessary conditions for the production of sound?

TEA [102]

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Answer: Something that's vibrating, and you also need medium for those vibrations to start in.

I hope this helped!

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2 years ago

A ball rolls 12m in 2.0s. What is the ball’s average velocity?

USPshnik [31]

Answer:

6 m/s

Explanation:

12m / 2s = 6 m/s

Hope that's the answer you seek.

5 0

2 years ago

What is true about energy that is added to a closed system?

Setler [38]

The correct answer is B

6 0

3 years ago

Read 2 more answers

what will happen to the brightness of the other bulbs in a series circuit if any of the bulbs were to burn out?

Ivenika [448]

Answer:

not work.

Explanation:

if u are saying in a series circuit...

if 1 build burns out and theres other bulbs the circuit wont work anymore.

6 0

2 years ago

The plates of a spherical capacitor have radii 6.25 cm and 15.0 crn. The space between the two spheres is filled with a material

aleksklad [387]

Answer:

Capacitance is 0.572×10⁻¹⁰ Farad

Explanation:

Radius = R₁ = 6.25 cm = 6.25×10⁻² m

Radius = R₂ = 15 cm = 15×10⁻² m

Dielectric constant = k = 4.8

Electric constant = ε₀ = 8.854×10⁻¹² F/m

ε/ε₀=k

ε=kε₀

$Capacitance\ (C)=\frac{4\pi k\epsilon_0 R_1\times R_2}{R_2-R_1}\\\Rightarrow C=\frac{4\pi 4.8\times 8.854\times 10^{-12}\times 15\times 10^{-2}\times 6.25\times 10^{-2}}{15\times 10^{-2}-6.25\times 10^{-2}}\\\Rightarrow C=0.572\times 10^{-10}\ Farad$

∴ Capacitance is 0.572×10⁻¹⁰ Farad

3 0

2 years ago