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SIZIF [17.4K]
3 years ago
15

4.5 billion km, the average separation between the sun and Neptune (report answer in hours). How long does it take light to trav

el each of the following distances?
Physics
1 answer:
Liula [17]3 years ago
4 0

Answer:

t = 4.17 hours

Explanation:

given,

The distance between Sun and Neptune, d = 4.5 billion Km

                                                                         = 4.5 x 10⁹ Km

                                                                          = 4.5 x 10¹¹ m

The velocity of light, c = 3 x 10⁸ m/s

The velocity is always equal to displacement by the time.

                                           <em>V = d / t    m/s</em>

∴                                           t = d / V

                                               = 4.5 x 10¹¹ m / 3 x 10⁸ m/s

                                               = 15,000 s

                                               = 4.17 h

Hence, the time taken by the light rays to reach the Neptune is, t = 4.17 h

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1. sturdy shelter

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Explanation:

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3 years ago
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The current in a hair dryer measures 11 amps. The resistance of the hair dryer is 12 ohms. What is the voltage?
Valentin [98]

Voltage is given by the formula

V = IR (Ohms law)

where V is the Voltage

I is the current

and R is the Resistance

Here it is given that the current is I=11

Resistance is R =12

so plugging this in the formula

V = IR

V= 11 * 12

V= 132 Volts

So the Voltage for the given dryer is 132 Volts

8 0
4 years ago
A crate is given a big push, and after it is released, it slides up an inclined plane which makes an angle 0.52 radians with the
vovangra [49]

Answer:

a = 8.951 m/s²

Explanation:

given,

angle = 0.52 radians

μ_s = 0.84

μ_k = 0.48

acceleration = ?

using

F +  f = m a

mg sin θ +  μk mg cos θ = m a

a = g sin θ  + μk g cos θ

a = 9.8 x  sin 0.52 + 0.48 x 9.8 x  cos 0.52

a = 4.869 + 4.082

a = 8.951 m/s²

the magnitude of acceleration is a = 8.951 m/s²

8 0
3 years ago
A piano tuner stretches a steel piano wire with a tension of 1070 N . The wire is 0.400 m long and has a mass of 4.00 g . A. Wha
pychu [463]

A. 409 Hz

The fundamental frequency of a string is given by:

f_1=\frac{1}{2L}\sqrt{\frac{T}{m/L}}

where

L is the length of the wire

T is the tension in the wire

m is the mass of the wire

For the piano wire in this problem,

L = 0.400 m

T = 1070 N

m = 4.00 g = 0.004 kg

So the fundamental frequency is

f_1=\frac{1}{2(0.400)}\sqrt{\frac{1070}{(0.004)/(0.400)}}=409 Hz

B. 24

For this part, we need to analyze the different harmonics of the piano wire. The nth-harmonic of a string is given by

f_n = nf_1

where f_1 is the fundamental frequency.

Here in this case

f_1 = 409 Hz

A person is capable to hear frequencies up to

f = 1.00 \cdot 10^4 Hz

So the highest harmonics that can be heard by a human can be found as follows:

f=nf_1\\n= \frac{f}{f_1}=\frac{1.00\cdot 10^4}{409}=24.5 \sim 24

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3 years ago
What is the Alternative Name for responding varible
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Dependent Variable=Responding Variable.
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