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V125BC [204]
3 years ago
7

Draw the major organic product in the reaction scheme. Be sure to clearly show stereochemistry (if applicable). The starting mat

erial is an alkyne where carbon 1 is bonded to cyclopentane and carbon 2 is bonded to H. Step 1 is N a N H 2. Step 2 is C H 3 I. Step 3 is sodium in liquid ammonia. Draw the major organic product.
Chemistry
1 answer:
never [62]3 years ago
5 0

Answer:

See answer below

Explanation:

The picture below will show you the final product and mechanism.

In the first step, the NaNH₂ is a strong base, so, this base will substract the hydrogen from carbon 2, to generate a negative charge there, and then, carbon 2 becomes a nucleophyle.

As a nucleophyle it will attack to the CH₃I in the next step, and it will attach to the CH₃.

The second step is just a regular step to reduce the triple bond of the alkyne to alkane or alkene, this will depend on the quantity of the reactant. In this case, an alkene.

Hope this helps,,,,,,k

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7 0
3 years ago
How many moles are in 2.8 g of Mg?
larisa86 [58]

Answer:

2.8 mg ≈ 0.12 mol

6 0
3 years ago
Compound A reacts with Compound B to form only one product, Compound C, and it's known the usual percent yield of C in this reac
frez [133]

Given :

Compound A reacts with Compound B to form only one product, Compound C.

The usual percent yield of C in this reaction is 40%.

10.0 g of A are reacted with excess Compound B, and 6.4 g of Compound C

To Find :

The theoretical yield of C.

Solution :

We know, % yield is given by :

\%\ yield = \dfrac{actual\ yield}{theoretical\ yield }\times 100

Putting given values , we get :

40 = \dfrac{6.4}{theoretical\ yield }\times 100\\\\theoretical\ yield=\dfrac{6.4\times 100}{40}\\\\theoretical\ yield=16\ g

Therefore, theoretical yield of C is 16 g.

Hence, this is the required solution.

7 0
3 years ago
If a system performs 147 kJ of work while receiving 47 kJ of heat, what is change in its internal energy?
Verdich [7]

Answer:

-100 kJ

Explanation:

We can solve this problem by applying the first law of thermodynamics, which states that:

\Delta U = Q-W

where:

\Delta U is the change in internal energy of a system

Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)

W is the work done by the system (it is positive if done by the system, negative if done on the system)

For the system in this problem we have:

W = +147 kJ is the work done by the system

Q = +47 kJ is the heat absorbed by the system

So , its change in internal energy is:

\Delta U = +47 - (+147) =-100 kJ

6 0
3 years ago
Fill in the coefficients that will balance the following reaction: a0Na + a1H2O → a2NaOH + a3H2
Alexandra [31]
Hey there !  :

<span>2 Na + 2 H2O = 2 NaOH + 1 H<span>2

</span></span>Sodium<span> + </span>Dihydrogen Monoxide<span> = </span><span>Natriumhydroxid</span><span> + </span>Hydrogen

Coefficients:

Reagents  :  Na = 2
                    H2O = 2
   

Products :  NaOH = 2
                  H2 = 1
4 0
4 years ago
Read 2 more answers
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