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Neporo4naja [7]
3 years ago
5

Which of the following actions would require the company to obtain a permit for discharge from the EPA? a. Releasing water back

into a stream after it was used in production with the only change being its temperature. b. Releasing water back into a stream after it was used in production, but in a state cleaner than it entered the factory. c. Releasing water into a pond on company property. d. Releasing water from a power plant cooling tower into the ocean. e. All of the above would require an EPA permi
Physics
1 answer:
Fiesta28 [93]3 years ago
6 0

Answer:

e. All of the above would require an EPA permit

Explanation:

For a company to discharge their by-products or waste such as wastewater, the company will need to obtain a specific permit for the Environmental Protection Agency (EPA). The EPA was formed to ensure that the integrity of the environment is not compromised. Thus, all of the options in the given question requires an EPA permit.

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Problem One: A beam of red light (656 nm) enters from air into the side of a glass and then into water. wavelength, c. and speed
Ivanshal [37]

Answer:

Part a)

f_w = f_g = 4.57 \times 10^{14} Hz

Part b)

\lambda_w = 492 nm

\lambda_g = 437.3 nm

Part c)

v_w = 2.25 \times 10^8 m/s

v_g = 2.0 \times 10^8 m/s

Explanation:

Part a)

frequency of light will not change with change in medium but it will depend on the source only

so here frequency of light will remain same in both water and glass and it will be same as that in air

f = \frac{v}{\lambda}

f = \frac{3 \times 10^8}{656 \times 10^{-9}}

f = 4.57 \times 10^{14} Hz

Part b)

As we know that the refractive index of water is given as

\mu_w = 4/3

so the wavelength in the water medium is given as

\lambda_w = \frac{\lambda}{\mu_w}

\lambda_w = \frac{656 nm}{4/3}

\lambda_w = 492 nm

Similarly the refractive index of glass is given as

\mu_w = 3/2

so the wavelength in the glass medium is given as

\lambda_g = \frac{\lambda}{\mu_g}

\lambda_g = \frac{656 nm}{3/2}

\lambda_g = 437.3 nm

Part c)

Speed of the wave in water is given as

v_w = \frac{c}{\mu_w}

v_w = \frac{3 \times 10^8}{4/3}

v_w = 2.25 \times 10^8 m/s

Speed of the wave in glass is given as

v_g = \frac{c}{\mu_g}

v_g = \frac{3 \times 10^8}{3/2}

v_g = 2 \times 10^8 m/s

4 0
3 years ago
Which of the following is true about conduction? Question 2 options: It is heat transfer through direct contact It can only occu
kramer

Answer:

through direct contact

Explanation:

took the test!

3 0
3 years ago
I really need help with this to be able to pass this last semester this is about (Circular Motion ) on physics
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Question 1
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a= (9.98)^2/31.77=3.1350
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