Average acceleration = (change in speed) / (time for the change) .
Average acceleration = (13.2 - 6) / (6.32) = 7.2 / 6.32 = about <em>1.139... m/s²</em> .
Answer:
Theta1 = 12° and theta2 = 168°
The solution procedure can be found in the attachment below.
Explanation:
The Range is the horizontal distance traveled by a projectile. This diatance is given mathematically by Vo cos(theta) t. Where t is the total time of flight of the projectile in air. It is the time taken for the projectile to go from starting point to finish point. This solution assumes the projectile finishes uts motion on the same horizontal level as the starting point and as a result the vertical displacement is zero (no change in height).
In the solution as can be found below, the expression to calculate the range for any launch angle theta was first derived and then the required angles calculated from the equation by substituting the values of the the given quantities.
Answer : The final pressure in the two containers is, 2.62 atm
Explanation :
Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

Thus, the expression for final pressure in the two containers will be:


where,
= pressure of N₂ gas = 4.45 atm
= pressure of Ar gas = 2.75 atm
= volume of N₂ gas = 3.00 L
= volume of Ar gas = 2.00 L
P = final pressure of gas = ?
V = final volume of gas = (4.45 + 2.75) L = 7.2 L
Now put all the given values in the above equation, we get:


Thus, the final pressure in the two containers is, 2.62 atm
This is sort of simple. 2 grams of X can combine with 4 grams of Y to form XY. Y is 2 times the amount of grams in X. So if there are 11 grams of X there are 22 grams of Y to form XY. Or you could take 11 divided by 2 is 5.5 and then multiply 4 by 5.5 to get 22. If this is wrong please tell me I would be very happy to know.
Answer:
Decreases/Reduces
Explanation:
Fill in the blank:
Consider the equation Work = Force X Distance.
<em>If a machine increases the distance over which a force is exerted, the force
</em>
<em>required to do a given amount of work</em> .........
If the work is a constant value, then by isolating force from the equation, we get:
Force = Work / Distance
By increasing the value of the Distance, then the quotient Work. Distance diminishes, and therefore the required force decreases (diminishes, reduces)
Answer: Decreases/Reduces