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snow_tiger [21]
3 years ago
8

A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15 kilometers away from point

A. What are the total distance and total displacement of the truck? A. The total distance is 105 kilometers, and the total displacement is 15 kilometers east. B. The total distance is 105 kilometers, and the total displacement is 45 kilometers east. C. The total distance is 60 kilometers, and the total displacement is 60 kilometers east. D. The total distance is 60 kilometers, and the total displacement is 45 kilometers east. E. The total distance is 105 kilometers, and the total displacement is 75 kilometers east.
Physics
2 answers:
nata0808 [166]3 years ago
6 0

A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15 kilometers away from point A.

Displacement=15km east

Distance=60+(60-15)=105km

ans is A. The total distance is 105 kilometers, and the total displacement is 15 kilometers east.

sineoko [7]3 years ago
3 0

Answer:

a

Explanation:

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<h2><em><u>Answ</u></em><em><u>er</u></em><em><u>:</u></em><em><u>-</u></em></h2>

\pink{\bigstar} The acceleration of the wheelchair is \large\leadsto\boxed{\tt\purple{0.5625 \: m/s^2}}

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<h3>• <u>Given</u><u>:</u><u>-</u></h3>

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<h3>• <u>To</u><u> </u><u>Find</u><u>:</u><u>-</u></h3>

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<h3>• <u>Solution</u><u>:</u><u>-</u></h3>

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\pink{\bigstar} \large\underline{\boxed{\bf\green{v^2 - u^2 = 2as}}}

where,

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• <u>S</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>the</u><u> </u><u>values</u><u> </u><u>in</u><u> </u><u>th</u><u>e</u><u> </u><u>Formula</u><u>:</u><u>-</u>

➪ \sf (1.5)^2 - (0)^2 = 2 \times a \times 2

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➪ \sf 2.25 - 0 = 4 \times a

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➪ \sf 2.25 = 4 \times a

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➪ \sf a = \dfrac{2.25}{4}

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★ \large{\bold\red{a = 0.5625 \: m/s^2}}

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⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Therefore, the acceleration of the wheelchair is 0.5625 m/s².

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