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Ghella [55]
3 years ago
14

A gate in an irrigation canal is constructed in the form of a trapezoid 2 m wide at the bottom, 38 m wide at the top, and 2 m hi

gh. It is placed vertically in the canal so that the water just covers the gate. Find the hydrostatic force on one side of the gate.
Note that your answer should be in Newtons, and use g = 9.8 m/s2.
Physics
1 answer:
mylen [45]3 years ago
4 0

Answer:

Explanation:

Area of trapezoid =[(2 + 38) / 2 ] x 2 = 40 sq m .

Pressure at the centre of the trapezium

= h d g = 1 x 10³ x 9.8 N / m²  ( height of centre is 1 m )

= 9800 N /m²

Total force required = pressure at the centre x total area

9800 x 40 = 392 x 10³ N.

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Oliga [24]
D cuz Negative will not repeal it will push away
6 0
3 years ago
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Particles q1 = -53.0 uc, q2 = +105 uc, and
Nimfa-mama [501]

Answer:

-180.38\ \text{N}

Explanation:

q_1=-53\ \mu\text{C}

q_2=105\ \mu\text{C}

q_3=-88\ \mu\text{C}

r = Distance between the charges

r_{12}=0.5\ \text{m}

r_{23}=0.95\ \text{m}

r_{13}=1.45\ \text{m}

k = Coulomb constant = 9\times 10^9\ \text{Nm}^2/\text{C}^2

Net force is given by

F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}

The force on the particle q_1 is -180.38\ \text{N}.

8 0
3 years ago
Which of the following describes the renewability of utility-scale wind energy?
schepotkina [342]

Unlimited, clean energy plant describes the renewability of utility-scale wind energy.

<h3>What is utility-scale wind energy?</h3>

Utility-scale wind turbines are installed in large, multi-turbine wind farms connected to the nation's transmission system. These turbines produce clean and unlimited energy.

So we can conclude that Unlimited, clean energy plant describes the renewability of utility-scale wind energy.

Learn more about energy here: brainly.com/question/13881533

6 0
2 years ago
The area of a triangle is 30 m². Using the equation A=12bh A = 1 2 b h , where b is base and h is height, solve for h if b = 3 m
Mama L [17]

Answer:

20 metres

Explanation:

Given that the area of a triangle is 30 square metres (m²). Using the equation A = 1/2bh, this is the formula for the triangle.

where b is base and h is height

Given that b = 3 metres.

To calculate h, Substitute b and A into the equation

30 = 1/2 × 3 × h

3h = 60

h = 60/3

h = 20 m

Therefore, h is equal to 20 metres

8 0
3 years ago
Two objects attract each other with a gravitational force of magnitude 9.20×10^-9 N when separated by 19.2 cm. If the total mass
melamori03 [73]
The gravitational force between two objects may be calculated by the equation,
                                      F = G x (m1 x m2) / d²
where G is universal gravitational constant, m1 and m2 are the masses of two bodies and  d is the distance between them. Substituting the known values,
                      9.20 x 10^-9 = (6.673 x 10^-11) (5.01 kg x m2) / (0.192m)²
The value of m2 is approximately 1.01 kg.
8 0
3 years ago
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