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madreJ [45]
3 years ago
8

Riley is doing an experiment working with friction. He wants to find two ways to modify an object that could increase or decreas

e the same type of friction
Physics
2 answers:
Dmitrij [34]3 years ago
8 0
If the type of friction is sliding friction, it may be increased by increasing the roughness of the surface and may be decreased by smoothing the surface or applying a lubricant.
elena-14-01-66 [18.8K]3 years ago
3 0

Answer:

As we know that friction force is a contact force which opposes the relative motion between two surfaces in contact.

So here we can change the force between two surface when they move relative to each other.

Here when Lubrication is used between two surface then the relative motion of two planes becomes easy. So by lubrication of the surface either by oil or by smoothing the plane we can say that friction force will be reduced.

Also friction force depends on the effective contact points between two surfaces. So as we increase the contact points between two surfaces then the effective frictional force will increase.

Also we know that friction force is given by

F_f = \mu F_n

now as we increase the normal force between two contact planes either by increasing the weight or by applying normal external force we can say that friction force will increase.

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a) Cumulus is 100% the correct answer

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Which of the following statements is NOT correct?
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D:if the
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Which statements describe vectors?
laila [671]

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Vectors have a size and direction. Each of the existing vector quantity has a magnitude and a direction. Having direction along with the magnitude is the difference of a vector quantity from a scalar quantity. Vectors are indicates with arrows.

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John is carrying a shovelful of snow. The center of mass of the 3.00 kg of snow he is holding is 15.0 cm from the end of the sho
Andru [333]

Answer:

James is correct here as the force of hand pushing upwards is always more than the force of hand pushing down

Explanation:

Here we know that one hand is pushing up at some distance midway while other hand is balancing the weight by applying a force downwards

so here we can say

Upwards force = downwards Force + weight of snow

while if we find the other force which is acting downwards

then for that force we can say that net torque must be balanced

so here we have

F_{down} L_1 = W_{snow} L_2

so here we have

F_{down} = \frac{L_2}{L_1} (W_{snow})

so here we can say that upward force by which we push up is always more than the downwards force

8 0
3 years ago
A particle of mass 4.5 × 10-8 kg and charge +5.4 μC is traveling due east. It enters perpendicularly a magnetic field whose magn
egoroff_w [7]

Answer:

0.00970 s

Explanation:

The centripetal force that causes the charge to move in a circular motion = The force exerted on the charge due to magnetic field

Force due to magnetic field = qvB sin θ

q = charge on the particle = 5.4 μC

v = velocity of the charge

B = magnetic field strength = 2.7 T

θ = angle between the velocity of the charge and the magnetic field = 90°, sin 90° = 1

F = qvB

Centripetal force responsible for circular motion = mv²/r = mvw

where w = angular velocity.

The centripetal force that causes the charge to move in a circular motion = The force exerted on the charge due to magnetic field

mvw = qvB

mw = qB

w = (qB/m) = (5.4 × 10⁻⁶ × 2.7)/(4.5 × 10⁻⁸)

w = 3.24 × 10² rad/s

w = 324 rad/s

w = (angular displacement)/time

Time = (angular displacement)/w

Angular displacement = π rads (half of a circle; 2π/2)

Time = (π/324) = 0.00970 s

Hope this Helps!!!

4 0
3 years ago
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