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madreJ [45]
4 years ago
8

Riley is doing an experiment working with friction. He wants to find two ways to modify an object that could increase or decreas

e the same type of friction
Physics
2 answers:
Dmitrij [34]4 years ago
8 0
If the type of friction is sliding friction, it may be increased by increasing the roughness of the surface and may be decreased by smoothing the surface or applying a lubricant.
elena-14-01-66 [18.8K]4 years ago
3 0

Answer:

As we know that friction force is a contact force which opposes the relative motion between two surfaces in contact.

So here we can change the force between two surface when they move relative to each other.

Here when Lubrication is used between two surface then the relative motion of two planes becomes easy. So by lubrication of the surface either by oil or by smoothing the plane we can say that friction force will be reduced.

Also friction force depends on the effective contact points between two surfaces. So as we increase the contact points between two surfaces then the effective frictional force will increase.

Also we know that friction force is given by

F_f = \mu F_n

now as we increase the normal force between two contact planes either by increasing the weight or by applying normal external force we can say that friction force will increase.

You might be interested in
A 6 kg block is attached to a massless rope that passes over a frictionless pulley. The pulley can be modeled as a uniformly den
scoundrel [369]

The effective mass of the system is 12 kg.

<u>Explanation:</u>

  • The effective mass of the system is given by the expression,

                    = mₓ + 1/2 m₁ + 2/5 m₂

  • In the above equations the subscript x denotes block B and the subscript 2 denotes the mass of the solid sphere and the subscript 1 denotes the pulley.
  • Expressing the above functions with the data given below. we have,

           = 6 kg + 1/2 (4 kg) + 2/5 (10 kg)

           =  12 kg.

with the findings above we can conclude that the effective mass of the system is 12 kg

6 0
3 years ago
A source emits sound with a frequency of 860 Hz. It is moving at 20.0 m/s toward a stationary reflecting wall. If the speed of s
Galina-37 [17]

Answer:

f_o=860\ Hz

Explanation:

Given:

  • original frequency of sound wave, f=860\ Hz
  • speed of the sound source, v_s=20\ m.s^{-1}
  • original speed of sound wave from the source, s=343\ m.s^{-1}

<u>According to the Doppler's effect:</u>

\frac{f_s}{f_o} =\frac{s+v_s}{s-v_o}

The sound is reflected from the wall and the source is moving towards the wall and observer is also riding the same source.

The velocity of the observer, v_o=-20\ m.s^{-1}

\frac{860}{f_o} =\frac{s+20}{s-(-20)}

f_o=860\ Hz

3 0
3 years ago
Read 2 more answers
Calculate the energy transfers in joules by a 4kW by appliances left for 2 minutes
Marianna [84]

Answer: 480 kJ

Explanation: Energy = power · time

E = Pt = 4000 W · 120 s = 480 000 J

5 0
3 years ago
You want to describe the harmonic motion of a swing. You find out that it takes 2 seconds for the swing to complete one cycle. W
vazorg [7]

Answer: Frequency= 0.5 Hz

Period= 2s

Explanation:

2 sec= 0.5 Hz

0.5Hz= 2 sec

4 0
4 years ago
You need to estimate the floor area of your unusual oval shaped living room from memory you remember that it is longer than wide
REY [17]

Answer:

Our estimate not done correctly because the width was unrealistic.

Explanation:

Given that,

Length = 6 m

Width = 0.5 m

We need to calculate the area of rectangular floor

Using formula of area

A=l\times w

Where, l = length

w= width

Put the value into the formula

A=6\times0.5

A=3\ m^2

We need to find why this estimate not done correct

Using given data

We can say that,

We assume width was unrealistic.

The length of room is 6 m.

We know that,

1\ m=3.28\ feet

So, the length would be 20 feet.

The width of room is 0.5 m.

The width of room would be 1.64 feet.

So, the area will be

A=20\times1.64

A=32.8\ feet^2

Hence,  Our estimate not done correctly because the width was unrealistic.

4 0
3 years ago
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