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Tcecarenko [31]
3 years ago
7

B) Calculate the net work required to bring a 1300 kg car moving at 30 m/s to rest.

Physics
1 answer:
prohojiy [21]3 years ago
5 0

I Lolo my name is keshav and

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An object has a mass of 5.20g. The mass of the object in kg is​
vampirchik [111]

Answer:

0.0520kg

Explanation:

divide by 1000

8 0
3 years ago
A
asambeis [7]

Answer:

22Volts

Explanation:

The pd at the terminal is known as the emf

Since there are Ten 2.2V cells

Terminal voltage = number of cells * pd of one cell

Terminal voltage = 10 * 2.2

Terminal voltage = 22V

Hence the pd at the battery terminals​ is 22Volts

4 0
2 years ago
Which of the following would be the S I unit to use in measuring the temperature of a hot liquid a. Ampere b. Mole c. Celsius d.
rusak2 [61]

It would be C Celsius just took k12 test

5 0
3 years ago
Read 2 more answers
a 2.0-mole sample of an ideal gas is gently heated at constant temperature 330 k. it expands from initial volume 19 l to final v
shutvik [7]
Isothermal Work =  PVln(v₂/v₁)

PV = nRT =  2 mole * 8.314 J/ (k.mol) * 330 k = 5487.24 J

Isothermal Work =  PVln(v₂/v₁)            v₂ = ? v₁ = 19L, 

1.7 kJ = (5487.24)In(v₂/19)

1700 = (5487.24)In(v₂/19)

In(v₂/19) = (1700/5487.24) = 0.3098

In(v₂/19) = 0.3098

(v₂/19) = e^{0.3098}


v₂  =  19* e^{0.3098}

v₂ = 25.8999

v₂ ≈ 26 L        Option b.
6 0
3 years ago
a car travels from station A to B at 30kmph during its return trip A it travels 30 km pH for the first half distance and it 70 k
8_murik_8 [283]

Explanation:

If you cannot visualize it, just assume that the distance from station A to B is 420km. Each half is 210km.

When the car travels from A to B, it takes 420/30 = 14 hours.

When the car travels from B to the halfway point, it takes 210/30 = 7 hours.

When the car travels from the halfway point to A, it takes 210/70 = 3 hours.

Total time taken = 14 + 7 + 3 = 24 hours.

Total distance = 420km * 2 = 840km.

Hence, the average speed of the car is 840/24 = 35km/h.

3 0
3 years ago
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