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Vilka [71]
3 years ago
9

When the moon orbits the Earth, it has velocity. Inertia would make the moon continue in a straight line instead of orbiting at

that velocity. The fact that it orbits at the same distance t tells you that ________
Physics
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

...there is an external force causing the moon not to continue in a straight line.

Explanation: According to Newton's first law of motion, every object will continue in its state of rest or uniform motion along a straight line unless acted upon by an external force.

The  external force causing the moon not to continue in a straight line is the force of gravitational attraction between the earth and the moon. This is in accordance to Newton's universal law of gravitation which states that every object attracts another object with a force that is directly proportional to the product of the masses of the objects and inversely proportional the the square of the distance between them. Also in this case, the gravitational pull between the moon and the earth is equivalent to the centripetal force that keeps the moon towards the earth, the earth being the center of motion for the moon. Recall that if the moon is orbiting the earth, then certainly the earth becomes the center of its motion.

Therefore the moon will only continue in a straight line in absence of the earth's gravitational pull.

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According to newton's first law, what is required to make an object slow down?
Luden [163]
I believe it is friction

3 0
3 years ago
Read 2 more answers
E)
guapka [62]

Answer:

Pressure, P = 32666.66 Pa

Explanation:

It is given that,

Surface area of foot of Bimaba is 150 cm² or 0.015 m².

Her weight is 50 kg

We need to find the pressure does she exert on the ground, as she stands on  her one foot. The force acting per unit area is called pressure. It can be given by :

P=\dfrac{F}{A}\\\\P=\dfrac{mg}{A}\\\\P=\dfrac{50\times 9.8}{0.015}\\\\P=32666.66\ Pa

So, the pressure is 32666.66 Pa.

7 0
3 years ago
If you wanted the pitch of a horn to drop relative to an observer, which way would you move the horn, relative to where that obs
Vladimir [108]
We assume that horn releases sound of constant frequency. In order for observer to observe different frequency either horn or observer or both must move.

This happens due to Doppler effect. It states that when position of source of sound and observer relative to each other changes, the observed frequency also changes. If the source emits sound of constant frequency than observed frequency will be either higher or lower than original.

When distance between source and observer increases the observed frequency will be lower. This is because same number of sound waves must cover greater distance so they have greater wavelength.
When distance between source and observer decreases the observed frequency will be higher. This is because same number of sound waves must cover smaller distance so they have smaller wavelength. 

Wavelength and frequency are inversely proportional meaning when one increases the other drecreases.

From this explanation we can find answer for our question. <span>If we wanted the pitch of a horn to drop relative to an observer we need to move horn away from an observer.</span>
3 0
3 years ago
( Find the value of the following in ms-1<br> 54kmhr
Darina [25.2K]

Answer:

54 × 5/18 = 15m/s

Explanation:

to convert km/hr to m/s you multiply by 5/18

6 0
1 year ago
Two cylindrical rods, one copper and the other iron, are identical in lengths and cross-sectional areas. They are joined, end to
Pie

Answer:

Vc = 2.41 v

Explanation:

voltage (v) = 16 v

find the voltage between the ends of the copper rods .

applying the voltage divider theorem

Vc = V x (\frac{Rc}{Rc + Ri})

where

  • Rc = resistance of copper = \frac{ρl}{a}  (l = length , a = area, ρ = resistivity of copper)
  • Ri = resistance of iron = \frac{ρ₀l}{a}  (l = length , a = area, ρ₀ = resistivity of copper)

Vc =  V x (\frac{\frac{ρl}{a}}{\frac{ρl}{a} + \frac{ρ₀l}{a}})

Vc = V x (\frac{ρ x (\frac{l}{a})}{(ρ + ρ₀) x (\frac{l}{a})})

Vc = V x (\frac{ρ}{ρ + ρ₀})

where

  • ρ = resistivity of copper = 1.72 x 10^{-8} ohm.meter
  • ρ₀ = resistivity of iron = 9.71 x 10^{-8} ohm.meter

Vc = 16 x (\frac{1.72 x 10^{-8}}{1.72 x 10^{-8} + 9.71 x 10^{-8}})

Vc = 2.41 v

5 0
3 years ago
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