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Vilka [71]
3 years ago
9

When the moon orbits the Earth, it has velocity. Inertia would make the moon continue in a straight line instead of orbiting at

that velocity. The fact that it orbits at the same distance t tells you that ________
Physics
1 answer:
Sholpan [36]3 years ago
8 0

Answer:

...there is an external force causing the moon not to continue in a straight line.

Explanation: According to Newton's first law of motion, every object will continue in its state of rest or uniform motion along a straight line unless acted upon by an external force.

The  external force causing the moon not to continue in a straight line is the force of gravitational attraction between the earth and the moon. This is in accordance to Newton's universal law of gravitation which states that every object attracts another object with a force that is directly proportional to the product of the masses of the objects and inversely proportional the the square of the distance between them. Also in this case, the gravitational pull between the moon and the earth is equivalent to the centripetal force that keeps the moon towards the earth, the earth being the center of motion for the moon. Recall that if the moon is orbiting the earth, then certainly the earth becomes the center of its motion.

Therefore the moon will only continue in a straight line in absence of the earth's gravitational pull.

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Explain why liquids solidify when they are cooled.
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Because the molecules that move freely begin to compact closer together, with less heat, means less molecular activity. 
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3 years ago
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A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

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4 0
3 years ago
In Challenge Example 11.9 (p. 280), after the explosion, suppose that the m1 fragment shot directly north at 12 m/s and the m3 f
Inga [223]

The question is incomplete. The mass of the object is 10 gram and travelling at a speed of 2 m/s.

Solution:

It is given that mass of object before explosion is,m = 10 g

Speed of object before explosion, v = 2 m/s

Let $m_1, m_2 \text{ and}\ m_3$ be the masses of the three fragments.

Let $v_1, v_2 \text{ and}\ v_3$ be the velocities of the three fragments.

Therefore, according to the law of conservation of momentum,

$mv=m_1v_1 +m_2v_2+m_3v_3$

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So the x- component of the velocity of the m2 fragment after the explosion is,

$3v_{2x} = 20$

∴ $v_{2x} = 6.67 \ m/s$

6 0
3 years ago
This should be correct
sweet-ann [11.9K]

Maybe it is, maybe it isn't.  We can't tell, until we see what "this" is. 

Show us a drawing, an equation, an expression, a statement ... something !

5 0
3 years ago
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