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astraxan [27]
3 years ago
7

Which type of electromagnetic waves make up the colors of a rainbow seen after a storm?

Physics
2 answers:
agasfer [191]3 years ago
5 0

Answer: A.) Visible light

Explanation: Edge 2020 good luck friend ^__^

coldgirl [10]3 years ago
3 0

Answer:

we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.

Hence, option A is correct.

Explanation:

Generally, after the storm, we can witness the presence of a rainbow with our naked eyes. Rainbow, visible to our eyes, consists of all the seven constituent colors of white light. Those seven colors range from violet to red, all having different wavelengths. When water particles present in our atmosphere get exposed to light, all the constituent colors of a white light tend to deviate at a variety of angles. It happens due to their refraction through water particles; thus, a spectrum is obtained.

As we cannot see X-rays, UV rays, and infrared waves through our naked eye, visible light is the kind of electromagnetic wave that makes anyone able to see the objects.  

Please note that all the constitute colors of a beautiful rainbow associate with the visible region of the electromagnetic spectrum.

Therefore, we conclude that visible light is that electromagnetic wave that makes up the colors of a rainbow seen after a storm.

Hence, option A is correct.

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The intensity of a sound wave at a fixed distance from a speaker vibrating at 1.00 kHz is 0.750 W/m2. (a) Determine the intensit
sveticcg [70]

Answer:

a)   I = 3.63 W / m² , b)   I = 0.750 W / m²

Explanation:

The intensity of a sound wave is given by the relation

         I = P / A = ½ ρ v (2π f s_{max})²

         I = (½ ρ v 4π² s_{max}²) f²

a) with the initial condition let's call the intensity Io

        cte = (½ ρ v 4π² s_{max}²)

         I₀ = cte s² f₀²

        I₀ = cte 10 6

If frequency is increase f = 2.20 10³ Hz

         I = constant (2.20 10³) 2

         I = cte 4.84 10⁶

let's find the relationship of the two quantities

        I / Io = 4.84

        I = 4.84 Io

        I = 4.84 0.750

        I = 3.63 W / m²

b) in this case the frequency is reduced to f = 0.250 10³ Hz and the displacement s = 4 s or

        I = cte (f s)²

        I = constant (0.250 10³ 4)²

 

        I = cte 1 10⁶

         

the relationship

        I / Io = 1

        I = Io

        I = 0.750 W / m²

6 0
2 years ago
You will now examine the relationship between the number of field lines through a surface and the tangle betwcen A and E) angle
nikitadnepr [17]

Answer:

a. cosθ b. E.A

Explanation:

a.The electric flux, Φ passing through a given area is directly proportional to the number of electric field , E, the area it passes through A and the cosine of the angle between E and A. So, if we have a surface, S of surface area A and an area vector dA normal to the surface S and electric field lines of field strength E passing through it, the component of the electric field in the direction of the area vector produces the electric flux through the area. If θ the angle between the electric field E and the area vector dA is zero ,that is θ = 0, the flux through the area is maximum. If  θ = 90 (perpendicular) the flux is zero. If θ = 180 the flux is negative. Also, as A or E increase or decrease, the electric flux increases or decreases respectively. From our trigonometric functions, we know that 0 ≤ cos θ ≤ 1 for  90 ≤ θ ≤ 0 and -1 ≤ cos θ ≤ 0 for 180 ≤ θ ≤ 90. Since these satisfy the limiting conditions for the values of our electric flux, then cos θ is the required trigonometric function. In the attachment, there is a graph which shows the relationship between electric flux and the angle between the electric field lines and the area. It is a cosine function  

b. From above, we have established that our electric flux, Ф = EAcosθ. Since this is the expression for the dot product of two vectors E and A where E is the number of electric field lines passing through the surface and A is the area of the surface and θ the angle between them, we write the electric flux as Ф = E.A  

4 0
3 years ago
A light bulb will glow when electrons flow through it. As the electron flow increases, the brightness increases as well. A stude
Inga [223]
The correct answer is: <span>Unscrew one light, if the others remain on it is a parallel circuit.</span>
6 0
3 years ago
Read 2 more answers
Calculate the acceleration of a mobile that at 4s is 32m from the origin, knowing that its initial speed is 10m / s.
ehidna [41]

Answer:

5.5 m/s^2

Explanation:

I believe this is the answer > using the formula a= v-v0/t

Hope this helps!

7 0
3 years ago
Read 2 more answers
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Charra [1.4K]

Answer:

Because they would naturally dye the test strips in the colors violet and red, regardless of their pH values

(would really appreciate the brainliest)

4 0
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