All categories

4 years ago

Which of the following statements is not a description of neptune?

Chemistry

2 answers:

pentagon [3]4 years ago

8 0

Answer:

It has no atmosphere

Explanation:

KIM [24]4 years ago

6 0

The appropriate answer is B. Has no atmosphere. Neptune is a gas giant and is the eight planet in the solar system. It has a thick atmosphere consisting of hydrogen, helium and methane. Neptune has at least eight moons with Triton being the largest.

Neptune has four rings which circle the planet. The rings are made of dust particles, similar to the rings of Saturn.

You might be interested in

Observations of the solar system support the nebular theory because

motikmotik

Answer:

Because all the planets orbit the sun in the same direction, along a circular flattened disk.

Explanation:

You're welcome bro, sorry for the late answer

6 0

4 years ago

Read 2 more answers

Which chemical equation is balanced? Question 4 options: CH4 + O2 → H2O + CO2 CH4 + O2 → 2H2O + CO2 6CH4 + O2 → 2H2O + 2CO2 CH4

Alexxx [7]

Answer:

CH4 + 2O2 → CO2 + 2H2O

Explanation: Hope this helps you.

6 0

3 years ago

Read 2 more answers

List 5 chemical properties of water??

Marat540 [252]

Answer:

In the presence of a strong electron donor (strong reducing agent), water serves as an oxidizing agent. In the presence of a strong electron acceptor (strong oxidizing agent), water serves as a reducing agent.
On-water reactions are a group of organic reactions that take place as an emulsion in water and have an unusual reaction rate acceleration compared with (i) the same reaction in an organic solvent, or (ii) the corresponding dry media reaction.
Amphoteric nature : Water can act as both acid and base, which means that it is amphoteric in nature.
Hydrolysis reaction : Water has a very strong hydrating tendency due to its dielectric constant. It dissolves many ionic compounds. Some covalent and ionic compounds can be hydrolyzed in water.
Redox reactions : Electropositive elements reduce water to hydrogen molecule. Thus, water is a great source of hydrogen.

5 0

3 years ago

What happens when a solid is dissolved in a liquid

Drupady [299]

Answer:

adds more liquid

Explanation:

7 0

4 years ago

Problem page gaseous ethane ch3ch3 will react with gaseous oxygen o2 to produce gaseous carbon dioxide co2 and gaseous water h2o

iVinArrow [24]

$m(\text{CO}_2) = 2.24 \; \text{g}$

Ethene react with oxygen at a $2 : 7$ molar ratio:

$2\; \text{C}_2 \text{H}_6 (g) + 7\; \text{O}_2 (g) \to 6\; \text{H}_2{O} (g) + 4\; \text{CO}_2 (g)$

Convert the quantity of each reactant supplied to number of moles of particles:

$n(\text{C}_2\text{H}_6) = 0.60 \; \text{g} / 28.05 \; \text{g} \cdot \text{mol}^{-1} = 0.0214 \; \text{mol}$
$n(\text{O}_2) = 3.27 \; \text{g} / 32.00 \; \text{g} \cdot \text{mol}^{-1} = 0.102 \; \text{mol}$

The question stated not whether both reactants were used up in this process. Thus start by testing the assumption that e.g., ethene was used up while some oxygen gas were left unreacted (ethene as the <em>limiting </em>reagent.) Under this assumption, the relative availability of the two species, $n(\text{C}_2 \text{H}_6) /2$ and $n(\text{O}_2) /7$ (as seen in the balanced chemical equation) shall satisfy the relationship

$n(\text{O}_2) / 7 - n(\text{C}_2 \text{H}_6) / 2 > 0$

In other words,

$n(\text{O}_2)/7 > n(\text{C}_2 \text{H}_6)/2$

$n(\text{C}_2 \text{H}_6) / n(\text{O}_2) < 2/7 \approx 0.286$

Evaluating the expression $n(\text{C}_2 \text{H}_6) / n(\text{O}_2)$ with data given in the question yields approximately $0.210 < 0.286$ , which does satisfy the relationship. Hence the assumption holds and ethene is the limiting reactant.

The quantity of a reactant produced in a chemical reaction is related to its stoichiometric (of relating to proportions) relationship with the limiting reactant (or any of the reactants in case of more than one limiting reactant.) For this scenario, given the molar ratio $n(\text{C}_2\text{H}_6) : n( \text{CO}_2) = 2:4$ ,

$n(\text{CO}_2) = n(\text{C}_2\text{H}_6) \cdot (2 / 4) = 0.0510 \; \text{mol}$

$m(\text{CO}_2) = 0.0510 \; \text{mol} \times 44.01 \; \text{g} \cdot \text{mol}^{-1} = 2.24 \; \text{g}$

4 0

3 years ago