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bagirrra123 [75]
4 years ago
14

A space shuttle can accelerate at a rate of 2.5m/s squared. Given that, and the fact that the engines of the space shuttle can p

roduce a force of about 1,600,000N, determine the mass(in kilograms) of the space shuttle
Physics
2 answers:
Afina-wow [57]4 years ago
8 0

Answer:

640000 kg

Explanation:

Formula is

Force = mass * acceleration

Mass = force / acceleration

Mass = 1600000 / 2.5

Mass = 640000 kg

ira [324]4 years ago
4 0
Follow @bbkcaleb on Instagram upcoming artist
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A packing crate slides down an inclined ramp at constant velocity. Thus we can deduce thatA) a frictional force is acting on itb
torisob [31]

Answer:

A) a frictional force is acting on it

Explanation:

The crate is sliding down the inclined ramp at constant velocity: constant velocity means zero acceleration, a = 0. According to Newton's second law:

F = ma

this also means that the net force acting along the direction of the slope is zero.

Without frictional force, there would be only one force acting along this direction: the component of the weight of the crane parallel to the slope, acting downward:

W_p = mg sin \theta

where \theta is the angle of the incline. Therefore, the net force along this direction would not be zero. In order to have a net force of zero, there must be another force acting upward on the crate: and the only force that is possibly acting on the crate against its direction of motion is the frictional force, whose magnitude must be equal to W_p, in order to produce a net force of zero (and therefore, a zero acceleration).

8 0
4 years ago
I NEED HELP ON THIS QUESTION!
GarryVolchara [31]

Forward because things that are in motion stay in motion.

Hope that helped!

~Izzy

4 0
3 years ago
Read 2 more answers
Como anticipan la caída del proyectil, con movimiento parabólico para que el misil no haga daño
Elena L [17]

Answer:

Conociendo la velocidad inicial del proyectil y el angulo de lanzamiento con respecto ala horizontal.

Explanation:

Para poder anticipar la caída del proyectil es importante conocer la velocidad inicial del proyectil y el angulo de disparo del proyectil con respecto a la horizontal.

A continuación se presenta un diagrama o esquema donde se pueden ver estas variables y se explicaran a la brevedad:

Para poder encontrar el rango que es la máxima distancia horizontal recorrida por el proyectil debemos utilizar la siguiente ecuación:

x=(v_{o})_{x} *t\\where:\\(v_{o})_{x} = velocidad inicial  x-component [m/s]\\t= time [s]

Para poder encontrar el tiempo debemos utilizar la siguiente ecuación:

y=(v_{y} )_{o}*t-0.5*g*t^{2}  \\donde:\\(v_{y} )_{o}= velocidad inicial componente y [m/s]\\g = gravity = 9.81 [m/s^2]\\t = time [s]

En la anterior ecuación, igualamos y = 0, ya que cuando el proyectil cae al suelo la distancia vertical es cero. De esta manera podemos encontrar el tiempo t, ya que conocemos la velocidad inicial del proyectil en la componente y.

Seguidamente reemplazamos t en la primera ecuacion y encontramos la distancia x o el rango.

8 0
3 years ago
Due to human demand because of its importance to life, the Earth's most precious resource is 
pychu [463]
The answer is variant C because every living organism needs water to survive. A human can live without water only 6 days, after that period the most important organs start to shut down because of the lack of water.
3 0
3 years ago
Read 2 more answers
If it takes a ball dropped from rest 2.261 s to fall to the ground, from what height H was it released? Express your answer in m
algol [13]

Answer:

Height, H = 25.04 meters

Explanation:

Initially the ball is at rest, u = 0

Time taken to fall to the ground, t = 2.261 s

Let H is the height from which the ball is released. It can be calculated using the second equation of motion as :

H=ut+\dfrac{1}{2}at^2

Here, a = g

H=\dfrac{1}{2}gt^2            

H=\dfrac{1}{2}\times 9.8\times (2.261)^2

H = 25.04 meters

So, the ball is released form a height of 25.04 meters. Hence, this is the required solution.

7 0
3 years ago
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