A space shuttle can accelerate at a rate of 2.5m/s squared. Given that, and the fact that the engines of the space shuttle can p
2 answers:
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Answer:
Current in outer circle will be 15.826 A
Explanation:
We have given number of turns in inner coil
Radius of inner circle
Current in the inner circle
Number of turns in outer circle
Radius of outer circle
We have to find the current in outer circle so that net magnetic field will zero
For net magnetic field current must be in opposite direction as in inner circle
We know that magnetic field is given due to circular coil is given by
For net magnetic field zero
So