The mass of one mole of water it is 18 amu, but you need to find the mass of a molecule of water, therefore you calculate the mass of one mole of water, which is 18 amu and you divided by Avogadro's number which is 6,022 x 10^23. The result is 2,989 x 10^-23. Hope I helped you. If you have any questions ask :) Good luck.
The answer to your question is 4. I and F.
According to the solubility rules, a<span>ll chloride (Cl</span>-), bromide (Br-), and iodide (I-<span>) salts are </span>soluble<span> except for those of Ag</span>+, Pb2+, and Hg2 <span>2+. In this case, CuI2 is soluble because it is not included in the exception mentioned above. CuI2 should be soluble to water.</span>
Lol ok so i really don’t know sorry
The mole is simply an Avogadros number of anything( in this case Br atoms)
The Avogadro number is 6.022 x 10^23.
So no of moles = No of atoms / 6.022 x 10^23 = 2.03 x 10^24 / 6.022 x 10^23 = 3.37 Moles.