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torisob [31]
2 years ago
14

An ionic compound has a very negative heat of solution in water. Would you expect it to be soluble or insoluble in water?.

Chemistry
1 answer:
ddd [48]2 years ago
8 0

Answer:

It will be Insolube in water

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1.50μm2. Convert this to square meters.
Verizon [17]
1.50x10^6 m2 is the answer you're looking for 
6 0
3 years ago
What would the volume of gas be at 150 c if it had a volume of 693 ml at 45 c​
marissa [1.9K]

Answer:

\boxed{\text{922 mL}}

Explanation:

The pressure is constant, so we can use Charles' Law to calculate the volume.

\dfrac{V_{1}}{T_{1}} = \dfrac{V_{2}}{T_{2}}

Data:

V₁ = 693 mL; T₁ =  45 °C

V₂ = ?;           T₂ = 150 °C

Calculations:

(a) Convert temperature to kelvins

T₁ = (  45 + 273.15) = 318.15 K

T₂ = (150 + 273.15) = 423.15 K

(b) Calculate the volume

\dfrac{ 693}{318.15} = \dfrac{ V_{2}}{423.15}\\\\2.178 = \dfrac{ V_{2}}{423.15}\\\\V_{2} = 2.178 \times 423.15 = \boxed{\textbf{922 mL}}

5 0
3 years ago
A solution is prepared by dissolving 0.23 mol of chloroacetic acid and 0.27 mol of sodium chloroacetate in water sufficient to y
Sergio [31]

Answer:

c. chloroacetate ion

Explanation:

The chloroacetic acid, ClCH₂CO₂H, is a weak acid with Ka = 1.36x10⁻³. When this weak acid is in solution with its conjugate base, ClCH₂CO₂⁻ (From sodium chloroacetate) a buffer is produced. The addition of a strong acid as the HCl produce the following reaction

HCl + ClCH₂CO₂⁻ → ClCH₂CO₂H + Cl⁻.

Where the acid reacts with the chloroacetate ion to produce more chloroacetic acid

That means, the HCl reacts with the chloroacetate ion present in the buffer solution

Right answer is:

<h3>c. chloroacetate ion</h3>
8 0
2 years ago
Which of the following methods correctly describes the preparation of 1.00 L of an aqueous solution of 0.500 M NaOH?
djyliett [7]

Answer:

Place 20.0 g NaOH(s) in a flask and dilute to 1.00 L with water.

Explanation:

7 0
2 years ago
How much heat is required to raise the temperature of 250.0 g of mercury by 52 degrees * C with a specific heat of 4.18
Goryan [66]
Heat required = M * C * (delta T)
= (Mass)*(Specific heat)*(temperature change)
= 250 * 4.18* 52 = 54340Joules.

I solve when unit of specific heat is (J/gC) if have another unit please tell me
5 0
3 years ago
Read 2 more answers
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