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umka21 [38]
3 years ago
6

When 5.00 mol of benzene is vaporized at a constant pressure of 1.00 atm and at its normal boiling point of 80.1°C, 169.5 kJ are

absorbed and PΔV for the vaporization process is equal to 14.5 kJ.
What is the change of internal energy?


What is the change of enthalpy?


Is the change in entropy positive or negative for this process?


If the pressure would be only ½ atm, what are the changes of internal energy and enthalpy during vaporization (approximately)?


How much energy is absorbed?


Write the definition of the Gibbs Free Energy.


At the lower pressure, will the boiling point be higher or lower.

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

∆E=155kJ

Explanation:

Check attachment

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Answer:

Half-reactions:

Cr³⁺ + 1e⁻ → Cr²⁺; Zn → Zn²⁺ + 2e⁻

Net ionic equation:

2Cr³⁺ + Zn → 2Cr²⁺ + Zn²⁺

Explanation:

The Cr³⁺ is reduced to Cr²⁺:

<h3>Cr³⁺ + 1e⁻ → Cr²⁺ -Half-reaction 1-</h3>

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Twice the reduction of Cr:

2Cr³⁺ + 2e⁻ → 2Cr²⁺

Now this reaction + Oxidation of Zn:

2Cr³⁺ + 2e⁻ + Zn → 2Cr²⁺ + Zn²⁺ + 2e⁻

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3 years ago
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7. An element's most stable ion forms an ionic compound with chlorine having the formula XCl2. If the ion of element X has a mas
Serhud [2]

Answer:

The element is strontium and the number of neutrons it have is 51.

Explanation:

Based on the given information, the ionic compound is,  

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X2+ is the ion of the mentioned element

As mentioned in the given question, the number of electrons of the element X is 36 and as seen from the reaction the charge present on the ion is +2. Now the atomic number will be,  

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Now based on the given information, the mass number of the element is 89. Now the no. of neutrons will be,  

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