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kotegsom [21]
3 years ago
9

During which two phases would surfer’s most likely benefit

Physics
2 answers:
Strike441 [17]3 years ago
6 0

Answer:

d

Explanation:

Rzqust [24]3 years ago
6 0
D. Because there is little tidal change
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10 points and brainliest lol goteem
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I think it's D cuz D is the heliocentric theory
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Which statement is true regarding DC current? A. The electrons move back and forth. B. There can only be one voltage supplied. C
Kazeer [188]

Answer:

B

Explanation:

In a DC current, the current supplied is steady motion (a straight horizontal line in a graph) and this is what makes it had to transform. The alternating current takes a sine wave motion in a graph. This means is voltage varies from zero to peak and reverses polarity. The rate at which it achieves this is its frequency in Hertz.

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3 years ago
Occurs when an object's velocity decreases
ankoles [38]
The answer would be
Negative Acceleration
3 0
3 years ago
A package is dropped from an airplane flying at an altitude of 69.2 m with a velocity of 1.40 x 10^2 km/h. Calculate the horizon
Andrew [12]
69.2 m with a velocity of 1.40* 10^2 km/h.

5 0
3 years ago
Can someone help meeeeee... show how to solve it plzzzzzzzz
liubo4ka [24]
<h2>Right answer: 64 units</h2><h2></h2>

According to the law of universal gravitation, which is a classical physical law that describes the gravitational interaction between different bodies with mass:

F=G\frac{m_{1}m_{2}}{r^2}

Where:

F is the module of the force exerted between both bodies

G is the universal gravitation constant.

m_{1} and m_{2} are the masses of both bodies.

r is the distance between both bodies

In this case we have a gravitation force F_{1}=16units, given by the formula written at the beginning. Let’s rename the distance r as d:

F_{1}=G\frac{m_{1}m_{2}}{d^2}     (1)

And we are asked to find the gravitation force F_{2} with a given distance of \frac{d}{2}:

F_{2}=G\frac{m_{1}m_{2}}{({\frac{d}{2})}^{2}}      

F_{2}=G\frac{m_{1}m_{2}}{{\frac{d^{2}}{4}}}     (2)

The gravity constant is the same for both equations, and we are assuming both masses are constants, as well. So, let’s isolate G m_{1}m_{2} in both equations:

From (1):

Gm_{1}m_{2}=F_{1}{d}^{2}     (3)

From (2):

Gm_{1}m_{2}=F_{2}\frac{{d}^{2}}{4}     (4)

If (3)=(4):

F_{1}{d}^{2}=F_{2}\frac{{d}^{2}}{4}     (5)

Now we have to find F_{2}:

F_{2}=F_{1}{d}^{2}\frac{4}{{d}^{2}}      

F_{2}=4F_{1}     (6)

If F_{1}=16 units:

F_{2}=(4)(16 units)        

F_{2}=64 units>>>>This is the new force of attraction     

3 0
3 years ago
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