<span>The value of the constant needed to complete in joules to three significant figures is 2.18 x 10^-18 J.</span>
I think it depends on the temperature...
Answer:
F - M a force exerted by scales on student
M a = M (9.8 + 4.9) m/s^2 upwards chosen as positive
a = 1.5 g net acceleration of student due to force of scales
W =M g weight of student (actual weight)
Wapp = M 1.5 * g apparent weight (on scales) of student
Force [kgms^-2] = mass [kg] x acceleration [ms^-2]
Work = force x distance
Work = [kgms^-2] x [m]
Work = [kgm^2s^-2]
Answer:
e) 
J
Explanation:
= Magnitude of electric field = 5 V/m
= Area of window = 1.5 m²
= speed of electromagnetic wave = 3 x 10⁸ m/s
= time interval = 1 h = 3600 sec
radiation energy is given as
J
