The redshift of distant galaxy are larger than those of closer galaxies, which indicates that the galaxy is receding at a faster rate.
- The Universe was 5 percent its current size when light left objects now at redshift of <u>19</u>.
Reasons:
The size of the universe represented as a scale factor with relation to the redshift can be presented as follows;
Where;
a₀ = The current size of the Universe
a = The size of the early Universe = 5% of a
Therefore;
0.05 + 0.05·z = 1
- The redshift is of the observed light is, z = <u>19</u>
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Answer:False
Explanation:
Work is being done on a body when it causes displacement of body on the application of force
When we pull the door by a force it causes zero displacements of the door. So we can say that work done on it is zero.
Thus the above-given statement is false
Answer:
Most of us have experienced that pivotal peak of pain, anger or frustration in which we want to scream “I hate my life.” Yet, the feeling that a dark cloud has specifically settled over us and our experiences can feel pretty isolating. The truth is, no matter how singled out or overwhelmed we feel, and no matter what area we are struggling in, we are not alone. More than half of U.S. workers are unhappy with their job. One in 10 Americans struggles with depression. All of us have moments of utter despair. Escaping from this hopeless-seeming state may feel impossible. Yet, in reality, we are not doomed, and we are not powerless. No matter what our circumstances, we can all learn tools to help us emerge from the darkest moments in our lives.
155Ω
Explanation:
R = R ref ( 1 + ∝ ( T - Tref)
where R = conduction resistance at temperature T
R ref = conductor resistance at reference temperature
∝ = temperature coefficient of resistance for conductor
T = conduction temperature in degrees Celsius
T ref = reference temperature that ∝ is specified at for the conductor material
T = 600 k - 273 k = 327 °C
Tref = 300 - 273 K = 27 °C
R = 50 Ω ( 1 + 0.007 ( 327 - 27) )
R = 155Ω
In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t,
= 49.6/6 = 8.267 m/s
