Answer:
A. any change that results in the formation of new chemical substances.
Explanation:
Below is an attachment containing the solution.
25.55 grams of tetraphosphorus decaoxide could be produced by the reaction.
Explanation:
First the balanced chemical reaction of the production of tetraphosphorus decaoxide is to be known.
The chemical equation is
10 KClO3 + 3P4⇒ 3 P4010 + 10 KCl
The number of moles of KCLO3 will be calculated by the formula:
number of moles = mass of the compound given ÷ atomic mass of the compound
n = 37.1 ÷ 122.55 ( atomic mass of KClO3 is 122.55 gm/mole)
= 0.30 moles
From the stoichiometry
10 moles of KClO3 is required to produce 3 moles of P4O10
when 0.30 moles of KClO3 is used x moles of P4O10 is formed
thus, 3 ÷ 10 = x ÷ 0.30
= 0.09 moles of KClO3 is produced
To know the mass of P4O10 apply the formula
mass = number of moles × atomic mass
= 0.09 × 283.886 ( atomic mass of P4O10 is 283.88 gram/mole)
= 25.55 grams of P4O10 could be produced.
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Explanation:
Molar mass
The mass present in one mole of a specific species .
The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .
(a) S₈
Molar mass of of the atoms are -
sulfur, S = 32 g/mol.
Molar mass of S₈ = 8 * 32 g/mol. = 256 g/mol.
(b) C₂H₁₂
Molar mass of of the atoms are -
Hydrogen , H = 1 g/mol
Carbon , C = 12 g/mol
Molar mass of C₂H₁₂ = ( 2 * 12 ) + (12 * 1 ) = 36 g /mol
(c) Sc₂(SO₄)₃
Molar mass of of the atoms are -
sulfur, S = 32 g/mol.
oxygen , O = 16 g/mol.
scandium , Sc = 45 g/mol.
Molar mass of Sc₂(SO₄)₃ = (2 * 45 ) + ( 3 *32 ) + ( 12 * 16 ) = 378 g /mol
(d) CH₃COCH₃ (acetone)
Molar mass of of the atoms are -
Carbon , C = 12 g/mol
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molar mass of CH₃COCH₃ (acetone) = (3 * 12 ) + ( 1 * 16 ) + ( 6 * 1 ) = 58g/mol
(e) C₆H₁₂O₆ (glucose)
Molar mass of of the atoms are -
Carbon , C = 12 g/mol
oxygen , O = 16 g/mol.
Hydrogen , H = 1 g/mol
Molar mass of C₆H₁₂O₆ (glucose) = ( 6 * 12 ) + ( 12 * 1 ) + ( 6 * 16 ) = 108g/mol.
