All categories

3 years ago

Heat is transferred from the heating element to the pot to the boiling water. what is the most likely method of heat transfer?

Chemistry

2 answers:

mixer [17]3 years ago

8 0

I'm a little late but I'm pretty sure the answer is B

grandymaker [24]3 years ago

4 0

The answer is B) conduction

You might be interested in

How many electrons would be found in the Ion who’s symbol is I-

Vesnalui [34]

Answer:

Explanation:

Given symbol of the element:

I⁻

Number of electrons found in an ion with the symbol:

This is a iodine ion:

For an atom of iodine:

Electrons = 53

Protons = 53

Neutrons = 74

An ion of iodine is one that has lost or gained electrons.

For this one, we have a negatively charged ion which implies that the number of electrons is 1 more than that of the protons.

So, number of electrons = 53 + 1 = 54

The number of electrons in this ion is 54

6 0

2 years ago

How are all atoms alike

Andru [333]

Because all atoms are made from the same particles which are protons, neutrons, and electrons.

Hope this helped!!!

8 0

2 years ago

J5 protons and 74 electrons

Brrunno [24]

Answer:

ins the same

Explanation:

neutrons have no charge

8 0

3 years ago

Using at least two properties of ionic compounds, explain why cookware is not made from ionic compounds.

muminat

Answer:

They mostly dissolve in water, and they are poor conductors of heat.

7 0

2 years ago

Write the TOTAL IONIC EQUATION between zinc and hydrochloric acid.

Andreyy89

Answer : The net ionic equation will be,

$Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)$

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The balanced ionic equation between zinc and hydrochloric acid will be,

$Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)$

The ionic equation in separated aqueous solution will be,

$Zn(s)+2H^+(aq)+2Cl^-(aq)\rightarrow Zn^{2+}(aq)+2Cl^-(aq)+H_2(g)$

In this equation, $Cl^-$ is the spectator ion.

By removing the spectator ion from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

$Zn(s)+2H^+(aq)\rightarrow Zn^{2+}(aq)+H_2(g)$

8 0

3 years ago