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mote1985 [20]
3 years ago
13

A standing wave is established on a string that is fixed at both ends.

Physics
2 answers:
oksano4ka [1.4K]3 years ago
7 0

Answer:

d. The length of the string is equal to one-half of a wavelength.

Explanation:

For a standing waves vibrating with Fundamental Frequency will be vibrate in one loop so  Length 2 L =  λ    ⇒  L = 1/2 λ

liubo4ka [24]3 years ago
5 0

Answer:

d)The length of the string is equal to one-half of a wavelength (L = λ/2)

Explanation:

When a standing wave is established on string which is fixed at both ends,

Then the relation between length of the string and wavelength is given by

L = λ/2

In this scenario, the length of the string is equal to one-half of the wavelength.

Another possible case is when on end of the string is fixed and one end of the string is free, in such case, the length of the string is equal to one-quarter of the wavelength.

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An electromagnetic wave traveling through a vacuum has a wavelength of 1.5 × 10-1 meter. What is the period of this wave?
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Answer: (1) 5.0 x 10^ -10 s

Explanation:

1.5 x 10^-1 m / 3 x 10^8 = .5 x 10^-9

= 5 x 10^-10

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Luba_88 [7]

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The driver of a pickup truck accelerates from rest to a speed of 37 mi/hr over a horizontal distance of 215 ft with constant acc
Alona [7]

Answer:

Maximum shearing force developed in each of the two pegs during acceleration is 1830 lbf

Explanation:

First we will find the acceleration of pickup truck.

As, the acceleration is uniform, therefore we can use Newton's third equation of motion:

2as = V_{f}^{2}-V_{i}^{2}

First convert speed into ft/sec

1 mile/hr = 1.47 ft/sec

therefore,

37 mile/hr = 37 x 1.47 ft/sec

37 mile/hr =  54.39 ft/sec

with initial speed 0 ft/sec (starting from rest), using in equation of motion:

a = [(54.39 ft/sec)² - (0 ft/sec)²]/2(215 ft)

a = 6.88 ft/sec²

Now, the total shear force will be given by Newton's second law of motion:

F = ma

F = (460 lbm +72 lbm)(6.88 ft/sec²)

F = 3660 lbf

Now for the max shear force in each of the two pegs we divide total fore by 2:

Force in each peg = F/2 = (3660 lbf)/2

<u>Force in each peg = 1830 lbf</u>

4 0
4 years ago
What is the difference between mass and weight?
yuradex [85]
The answer is definitely A
8 0
3 years ago
Consider the force field and circle defined below. F(x, y) = x2 i + xy j x2 + y2 = 121 (a) Find the work done by the force field
kirza4 [7]

Answer: the work done by the force is 0

Explanation:

F (x², xy)

121 = 11²

so R = x² + y² = 11²

p = x². Q = xy

Δp/Δy = 0, ΔQ/Δx

using Green's theorem

woek = c_∫F.Δr = R_∫∫ ΔQ/Δx - Δp/Δy) ΔA

=  (x² + y² = 121)_∫∫ yΔA

now let x = rcosФ, y = rsinФ

ΔA = rΔrΔФ

so r from 0 to 11

and Ф from 0 to 2π

= 0_∫^2π   0_∫^11  rsinФ × rΔrΔФ

= 0_∫^2π SinФΔФ   0_∫^11  r²Δr

= [ -cosФ]^2π_0 [r³/3]₀¹¹ = ( -cos2π + cos0) (11³/3) = 0

therefore the work done by the force is 0

3 0
4 years ago
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