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3 years ago

According to Newton’s third law of motion, when a hammer strikes and exerts force on a nail, the nail...

Physics

1 answer:

salantis [7]3 years ago

3 0

Answer:

C) Exert an equal force back on the hammer

Explanation:

Every action has an equal and opposite reaction

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Sentence for cell wall

disa [49]

Plants have cell walls, but animals do not because otherwise we wouldn't be able to move.

8 0

4 years ago

A transformer is to be used to provide power for a computer disk drive that needs 6.4 V (rms) instead of the 120 V (rms) from th

Amanda [17]

Answer:

The current in the primary is 0.026 A

Explanation:

Using the formula

I1 = (V1/V2)*I2

we have

I1 = (6.4/120)*0.500

I1 = 0.026 A

8 0

3 years ago

Water flows through a first pipe of diameter 3 inches. If it is desired to use another pipe for the same flow rate such that the

Alborosie

Answer:

the diameter of the second pipe is 2.52 in

Explanation:

Given the data in the question;

We know that; the rate of flow is the same;

Av1 = Av2

v ∝ √h

$\frac{A1}{A2}$ = $\frac{V2}{V1}$

$\frac{A1}{A2}$ = √( $\frac{h2}{h1}$ )

( π/4.D1² / π/4.D2² ) = √( $\frac{h2}{h1}$ )

( D1² / D2² ) = √( $\frac{2h1}{h1}$ ) since second is double of first

( D1² / D2² ) = √( $\frac{2}{1}$ )

3² / D2² = √2

D2²√2 = 9

D2² = 9/√2

D2² = 9 / 1.4142

D2² = 6.364

D2 = √ 6.364

D2 = 2.52 in

Therefore, the diameter of the second pipe is 2.52 in

3 0

3 years ago

Light undergoes refraction as it travels from water to glass. The refractive index of water = 1.33 and refractive index of glass

cestrela7 [59]

Answer: 28°

Explanation:

Snell's law n₁sinθ₁ = n₂sinθ₂

1.33sin32 = 1.5sinθ₂

θ₂ =28°

3 0

3 years ago

7. A car is travelling along a road at 30 ms when a pedestrian steps into the road 55 m ahead. The

trasher [3.6K]

Answer: Car collide with man

Explanation:

Given

Speed of car is $u=30\ m/s$

Distance of the man from the car is $s=55\ m$

Reaction time $t_r=0.5\ s$

Rate of deceleration $a_d=-10\ m/s^2$

Distance traveled in the reaction time $d_o=30\times 0.5=15\ m$

Net effective distance to cover $d=55-15=40\ m$

Distance required to stop the car

$\Rightarrow v^2-30^2=2(-10)(s)\\\Rightarrow 0-900=-20s\\\Rightarrow s=45\ m$

Require distance is more than that of net effective distance. Hence, car collides with the man.

6 0

3 years ago