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Nady [450]
3 years ago
10

On a caterpillars map all distances are marked in kilometers . The caterpillars map shows the distance between two milkweed plan

ts is 4,012 milimeters what is the distance in kilometers
Physics
1 answer:
frutty [35]3 years ago
5 0

Answer:

The distance in kilometers is 4012 ×10^{-6} km.

Explanation:

We know that the conversion of 1 millimeters is equal to 10^{-3} meter. And then the conversion of 1 meter is equal to 10^{-3} km. Then the conversion of 1 millimeter to km will be

1 mm = 10^{-3} m

1 m = 10^{-3} km

So, 1 mm = 10^{-3}×10^{-3} km = 10^{-6} km.

As here the the distance is 4012 mm, then the distance in km will be

4012 mm = 4012 ×10^{-6} km.

So the distance is 4012 ×10^{-6} km.

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The Cassegrain design provides more compact (shorter) telescopes. Why? (Examine figures 2.4.2 and 2.4.3). The shorter design is
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Answer:

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5 0
3 years ago
One of the most efficient engines built so far has the following characteristics: combustion chamber temperature = 1900°C, exhau
suter [353]

Answer:

actual efficiency is  47.78 %

Carnot efficiency  is 67.65 %

power output is 5.20 × 10^3 hp

Explanation:

given data

temperature = 1900°C = 1900+ 273 K = 2173 K

exhaust temperature = 430°C = 430 + 273 K = 703 K

fuel = 7.0 × 10^9 cal

work = 1.4 × 10^10 J

to find out

actual efficiency  and Carnot efficiency and power output of engine

solution

first we find actual efficiency that is = work / heat input

put the value and

input energy  = 7.0 × 10^9 cal  (4.184 J/1 cal)  = 29.29 × 10^9 J

actual efficiency  =  1.4 × 10^10 / ( 29.29 × 10^9 )

actual efficiency  =  0.4778

actual efficiency is  47.78 %

and

Carnot efficiency  is = 1 - ( 703 / 2173 )

so Carnot efficiency  is  = 0.67648

Carnot efficiency  is 67.65 %

and

power output  = work / time

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power output = 3.88 × 10^6 W

power output = 3.88 × 10^6 W / 746 hp

so power output is 5.20 × 10^3 hp

5 0
3 years ago
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