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Nady [450]
3 years ago
10

On a caterpillars map all distances are marked in kilometers . The caterpillars map shows the distance between two milkweed plan

ts is 4,012 milimeters what is the distance in kilometers
Physics
1 answer:
frutty [35]3 years ago
5 0

Answer:

The distance in kilometers is 4012 ×10^{-6} km.

Explanation:

We know that the conversion of 1 millimeters is equal to 10^{-3} meter. And then the conversion of 1 meter is equal to 10^{-3} km. Then the conversion of 1 millimeter to km will be

1 mm = 10^{-3} m

1 m = 10^{-3} km

So, 1 mm = 10^{-3}×10^{-3} km = 10^{-6} km.

As here the the distance is 4012 mm, then the distance in km will be

4012 mm = 4012 ×10^{-6} km.

So the distance is 4012 ×10^{-6} km.

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Which gravitational force field dagram is drawn correctly?
VladimirAG [237]
The correct diagram is B:)
8 0
2 years ago
Read 2 more answers
A toolbox of mass 3.2kg is lowered by a rope from the roof to the ground. Find the acceleration of the toolbox when the force of
Lisa [10]

Answer:

The answer to your question is:

a) 2.7 m/s²

b) -3.6 m/s²

Explanation:

Data

mass of the toolbox = 3.2 kg

a = ?

F = 40 N and F = 20 N

g = 9.81 m/s²

Formula

Second law of motion = F = ma

                              a + g = F / m

                              a = F/m - g

a)                            a = 40/3.2 - 9.81

                              a = 2.69 ≈ 2.7 m/s²   positive up

b)                            a = 20/ 3.2 - 9.81

                              a = 6.25 - 9.81

                                  = - 3.56 ≈ - 3.6 m/s²  negative down

8 0
3 years ago
What is the net displacement of the particle between 0 seconds and 80seconds?
Ira Lisetskai [31]

Answer:

Option (A)

Explanation:

Displacement of a particle on a velocity time graph is represented by the area between the line representing velocity and x-axis (time).

Displacement of a particle from t = 0 o t = 40 seconds = Area of ΔAOB

Area of triangle AOB = \frac{1}{2}(\text{Base})(\text{height})

                                   = \frac{1}{2}(40)(4)

                                   = 80 m

Similarly, displacement of the particle from t = 40 to t = 80 seconds = Area of ΔBCD

Area of ΔBCD = \frac{1}{2}(40)(4)

                        = 80 m

Total displacement of the particle from t = 0 to t = 80 seconds,

= 80 + 80

= 160 m

Option (A) will be the answer.

7 0
3 years ago
Danny and Iskander sit on a see-saw. Iskander weighs 40 N and sits 1.2 meters from the pivot. Danny sits 0.8 m from the pivot an
Katena32 [7]

Answer:

60N

Explanation:

According to the principle of lever: a torque can control if an object will spin or not.

The torque Iskander cause is 40*1.2=48 N-m

So for balanced, Danny should cause the same torque.

48/0.8=60, Danny weigh 60N.

7 0
2 years ago
a spring has constant 250 Newton per meter. if it is stretched a distance of 0.1m, what is the reatoring force?what if it is str
svetlana [45]
At 0.1m, the restoring force would be 25 Newtons. It would probably not be possible to stretch to 5 meters because that would cause a restoring force of 1250 Newtons.
4 0
3 years ago
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