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3 years ago

Which of the following methods of improving air quality does not require advanced technology?

Physics

1 answer:

Kisachek [45]3 years ago

3 0

Conservation is a method of improving air quality

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T-Joe (65 kg) is running at 3 m/s. T-Brud (50 kg) is running at 4 m/s. What would be T-Joe's momentum?

Debora [2.8K]

Answer:

$P_J=195N$

Explanation:

From the question we are told that

$Mass\ of T-joe\ M_J=65\\Velocity\ of T-joe\ V_J=3m/s\\Mass of\ T-Brud\ M_B=50kg\\Velocity\ of T-Brud\ V_B=3m/s\\$

Generally the equation for momentum is mathematically given by

$P=mv$

Therefore

T-Joe momentum $P_J$

$P_J=65*3$

$P_J=195N$

5 0

2 years ago

A boy who exerts a 300-N force on the ice of a skating rink is pulled by his friend with a force of 75 N, causing the boy to acc

Jlenok [28]

Answer:

a is the answer

Explanation:

3 0

3 years ago

Read 2 more answers

A positively charged glass rod attracts object X. The net charge of object X:A.may be zero or negative.B.may be zero or positive

Damm [24]

Answer:A

Explanation:

A positively charged glass rod attracts object x. So, object x must be negatively charged or uncharged.

This occurs because opposite charges attract each other or either object x is uncharged and a negative charge is induced in it as glass rod approach the object x.

So option A is correct

8 0

2 years ago

A lion accelerates from 1.5 m/s to 1.0 m/s in 18.4 s. How far does the lion run during this time?

Lesechka [4]

Answer:

23 m

Explanation:

If acceleration is uniform then

distance = ( average velocity ) × time

= ( (initial velocity +final velocity )/2 ) × time

= (( 1.5 + 1.0) /2 ) × 18.4

= ( 2.5/2 ) × 18.4

= 1.25× 18.4

= 23 m

6 0

3 years ago

You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state

Aleks04 [339]

Explanation:

It is given that,

Height of the building, h = 44 m

Initial horizontal velocity, $u_x=ucos\theta=8.6\ m/s$

Initial vertical velocity, $u_y=usin\theta=10.5\ m/s$

It can be assumed to find the maximum height of the projectile and time taken to reach the maximum height.

The formula for the maximum height is given by :

$H=\dfrac{(u\ sin\theta)^2}{2g}$

g is the acceleration due to gravity

$H=\dfrac{(10.5)^2}{2\times 9.8}=5.625\ m$

The total maximum height, h' = h + H

$h'=44+5.625=49.625\ m$

The formula for the time of flight is given by :

$t_{max}=\dfrac{u\ sin\theta}{g}$

$t_{max}=\dfrac{10.5}{9.8}=1.07\ s$

Hence, this is the required solution.

3 0

3 years ago