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dybincka [34]
3 years ago
13

The ammeter below shows the current produced by a series of solar cells that contain zinc plates being used to power a simple se

ries circuit.
If the circuit’s resistance is 0.2 Ω, what voltage is supplied by the cells?


A) 750 v

B) 15 v

C) 3 v

D) 25 v

Physics
1 answer:
nataly862011 [7]3 years ago
8 0
The Ammeter shows:  I = 15 A,
The circuit resistance is R = 0.2  Ohms.
By the Ohm`s Law:
R = V / I or:
V = I · R
V = 15 A · 0.2 Ohms
V = 3 V
Answer: C ) 3 V.
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They both are part of electromagnetic radiation.

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Radio waves have lower frequency than visible waves.

Explanation:

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What is the only possible value of ml for an electron in an s orbital?
Archy [21]

Answer:

  • zero

Explanation:

m_l     is the magnetic quantum number.

The only possible value for the magnetic quantum number for an electron in an s orbital is 0.

The first three quantun numbers are:

  • n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...

  • l : Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.

       This quantum number is related to the type (or shape) of the orbital:

        For s orbitals l=0

        For p orbitals l=1

        For d orbitals l=2

         For f orbitals l=3

In this case, it is an s orbital, so we have l=0.

  • m_l , the third quantum number can have integer values  {from-l}   to    {+l}

       Since, for the s orbitals  l=0 , the only possible value for {m_l} is zero.

4 0
3 years ago
The final stages of a star's life depend on its mas. true or false?​
Diano4ka-milaya [45]

Answer:

TRUE

Explanation:

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5 0
3 years ago
A 2.0-kg object moving with a velocity of 5.0 m/s in the positive x direction strikes and sticks to a 3.0-kg object moving with
Andrej [43]

Answer:

5.4 J.

Explanation:

Given,

mass of the object, m = 2 Kg

initial speed, u = 5 m/s

mass of another object,m' = 3 kg

initial speed of another orbit,u' = 2 m/s

KE lost after collusion = ?

Final velocity of the system

Using conservation of momentum

m u + m'u' = (m + m') V

2 x 5 + 3 x 2 = ( 2 + 3 )V

16 = 5 V

V = 3.2 m/s

Initial KE = \dfrac{1}{2}mu^2 + \dfrac{1}{2}m'u'^2

              = \dfrac{1}{2}\times 2\times 5^2 + \dfrac{1}{2}\times 3 \times 2^2

              = 31 J

Final KE = \dfrac{1}{2} (m+m')V^2 = \dfrac{1}{2}\times 5 \times 3.2^2 = 25.6 J

Loss in KE = 31 J - 25.6 J = 5.4 J.

4 0
3 years ago
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