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vlada-n [284]
3 years ago
7

(HELPP NEEEDED NOW) Which example shows competition between members of the same population in a community? A pride of lions work

s together to bring down a water buffalo. A male lion chases after another lion that invaded its territory. A lion and a cheetah clash while stalking a gazelle. A pride of lions chases away a pack of hyenas trying to eat their kill.
Chemistry
1 answer:
klio [65]3 years ago
7 0

Answer:

C

Explanation:

A pride of lions working together suggests the opposite of competition.

Same comment about the water buffalo.

The answer is C. If the territory is invaded and the two males clash, that's competition.

A Cheetah is not part of the Lion's Pride.

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Your experiment requires 150 mL of 7.7 M NaOH. How many grams of NaOH will you need?
Elodia [21]
You have molarity and you have volume. Use the formula :
Molarity(M)= Moles(N)/Liter(L)            to get the solution. 
150 ml= .150 L
7.7 = N/.150
N=.1.155 moles of NaOH.
 And since you know the moles, use the molar mass to figure out the grams.
<span> (40g/mol NaOH) x (1.155mol) =  
46.2 g of NaOH.</span>
7 0
3 years ago
How would the concentration of silver ions compare in a 1.0 x 10-16 L saturated solution to a 1.5 x 10-16 L saturated solution?
VMariaS [17]
The second one is more concentrated as they both times with the same thing but the second one (1.5) is bigger
3 0
3 years ago
a 1.25g sample of ore containing iron pyrite (FeS2) was pulverized and ignited in air, converting the FeS2 to Fe2O3 and SO2(g).
svp [43]

Answer:

28.9%

Explanation:

Let's consider the following balanced equation.

2 FeS₂ + 11/2 O₂ ⇒ Fe₂O₃ + 4 SO₂

We can establish the following relations:

  • The molar mass of Fe₂O₃ is 159.6 g/mol
  • 1 mole of Fe₂O₃ is produced per 2 moles of FeS₂
  • 1 mole of Fe is in 1 mole of FeS₂
  • The molar mass of Fe is 55.84 g/mol

The amount of Fe in the sample that produced 0.516 g of Fe₂O₃ is:

0.516gFe_{2}O_{3}.\frac{1molFe_{2}O_{3}}{159.6gFe_{2}O_{3}} .\frac{2molFeS_{2}}{1molFe_{2}O_{3}} .\frac{1molFe}{1molFeS_{2}} .\frac{55.84gFe}{1molFe} =0.361gFe

The percent of Fe in 1.25 g of the ore is:

\frac{0.361g}{1.25g} .100\%=28.9\%

4 0
3 years ago
Look at the periodic table in Appendix 1. Name two elements that do not appear in order of their relative atomic masses.
e-lub [12.9K]

iodine which should appear before tellurium and argon which should appear after potassium

There is a 3rd one: nickel should appear before cobalt

8 0
3 years ago
Please Help ASAP........................ <br>​
Gennadij [26K]
C. Wavelength will increase
6 0
3 years ago
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