Calculate the molarity of a 10. 0% cacl₂ solution. The density of the solution is 1. 0835 g/cm³.
1 answer:
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Explanation:
Given formula:
ME=mv²+mgh
To make height the subject of the formula, follow the following procedures;
Subtract mv² from both side of equation
M.E - mv² =
mv² -
mv²+mgh
This gives:
M.E - mv² = mgh
Multiply both sides of the expression by
( M.E - mv² ) x
=
x mgh
h = ( M.E - mv² ) x
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Answer: The question has some missing details. The initial velocity given as u = -6.5i + 17j + 13k and the final velocity v = -2.8i + 17j -9.3k.
a) = (1.82i - 9.69k)m/s2
b) magnitude = 9.85m/s2
c) direction = 280.64 degree
Explanation:
The detailed and step is shown in the attachment.
