<span>Molarity
is expressed as the number of moles of solute per volume of the solution. We solve the problem above as follows:
0.1000 mol Mg(NO3)2 / L (.1 L) ( </span><span>148.3 g / mol ) = 1.483 g Mg(NO3)2
</span>0.1000 mol Sr(NO3)2 / L (.1 L) ( 211.63 g / mol ) = 2.116 g Sr(NO3)2
Hope this answers the question. Have a nice day.
Moles (mol) = mass (g) / molar mass (g/mol)
Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol
Hence moles of NaCl in the mixture is 0.372 mol.
Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.
mole % = (moles of desired substance / Total moles of the mixture) x 100%
Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
Total moles of mixture = moles of NaCl + KCl + LiCl
Mass of KCl = 3.74 g
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g / 74.6 g/mol = 0.050 mol
Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol
Total moles = 0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
= (0.372 mol / 0.652 mol) x 100%
= 57.06%
Hence, mixture has 57.06% of NaCl as the mole percentage.
Answer:
<em>Different rocks have high, medium, and low melting points.</em>
Explanation:
There is a considerable range of melting temperatures for different compositions of magma. All the silicates are molten at about 1200°C (when a part of rock) and all are solid when cooled to about 600°C. Often the silicates are grouped as high, medium and low-melting point solids.
2KClO3 --> 2KCl + 3O2
3 moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose.
Answer:
107g
Explanation:
Magnesium fluoride (MgF₂) has a molecular mass of:
Mg: 24,305 g/mol × 1 = 24,305 g/mol
F: 18,998 g/mol × 2 = 37,996 g/mol
MgF₂ = 24,305g/mol + 37,996g/mol = 62,301g/mol. That means the mass of 1,72 mol of MgF₂ is:
1,72 mol F₂ × (62,301g / 1mol) = <em>107g</em>
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I hope it helps!
