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Aleonysh [2.5K]
3 years ago
13

A toaster is plugged into a 132 volt household circuit it draws the amps of current If you use a toaster 2 hours a week how much

energy do you use in kWh
Physics
1 answer:
Ne4ueva [31]3 years ago
8 0
There is a missing data in the text of the problem: the current drawn is 0.5 A (found on internet)

Solution:
The power used by the toaster is the product between the voltage V and the current I:
P=VI=(132 V)(0.5 A)=66 W=0.066 kW

The toaster is used for a time of 2 hours: t=2h, therefore the energy used is equal to
E=Pt =(0.066 kW)(2 h)=0.132 kWh
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Consider a plastic rod that is being charged up by rubbing a wool cloth. It is then brought to an initially neutral metallic sph
anygoal [31]

Answer:

A) is repelled by the sphere

Explanation:

  • When a piece of plastic is rubbed with a wooden cloth, it sinks negatively
  • Let it change Q. So it is now allowed to touch the neutral zone. Therefore, there is a difference in the surface capacity of the two bodies, so that charge transfer takes place
  • Some of its negative charge is transferred to the metal sphere, now both the rod and the sphere are negatively charged and the same chargers as we know are repelled by each other.
  • so correct answer is A) is repelled by sphere
7 0
3 years ago
A car slams on the brakes to stop. The road pushes back up on the car with a normal force of 12,750 N and friction from the brak
ivann1987 [24]

Answer:

\displaystyle \mu_d=0.75

Explanation:

Coefficients of Friction

Objects in physical contact produce friction which usually manifests as thermal energy being dissipated in the surface where the objects are interacting. It's usually harder to start to move an object from rest, that keeps moving it at a constant speed on the same surface. That is why there are two different coefficients of friction: the static and the dynamic. As mentioned, the static coefficient \mu_s is greater than the dynamic coefficient \mu_d. The car is already moving and is attempting to stop. The coefficient of friction is defined as

\displaystyle \mu_d=\frac{F_r}{N}

Where Fr is the force of friction and N is the normal or the force the road pushes back up on the car. With the given data, we have

\displaystyle \mu_d=\frac{9,560\ N}{12,750\ N}

\displaystyle \boxed{\mu_d=0.75}

The coefficient of friction is dimensionless (doesn't have any units)

6 0
3 years ago
An object's
shusha [124]

The planet of an item will remain constant across the planet, but if you give it more mass, the gravitational force increases while the acceleration due to gravity remains constant.

<h3 /><h3>What is the difference between mass and weight?</h3>

The mass of the body is defined as the amount of matter a body has. It is denoted by m and its unit is kg. Mass is the quantity on which a lot of physical quantity depends.

Weight is defined as the amount of force an object exerts on the surface. It is given as the product of mass and the gravitational pull.

Mass is an independent quantity it never depends on the other. While weight is a dependent quantity that depends upon the gravitational pull.

The value of gravitational pull is different in the different parts of the universe. For example, on the earth, the value of gravitational acceleration is 9.81 m/sec².While on the moon it is g/6.

Weight is change according to the place or surrounding while the mass of the body is constant everywhere.

The planet of an item will remain constant across the cosmos, but if you give it more mass, the gravitational force increases while the acceleration of gravity remains constant.

If a planet's gravity weakens, the weight of that planet will likewise be altered. With an increase in mass, weight also rises.

Hence, the gravitational force increases while the acceleration due to gravity remains constant for the given case.

To learn more about the mass refer to the link;

brainly.com/question/19694949

#SPJ1

3 0
2 years ago
A conducting sphere of radius R1 carries a charge Q. Another conducting sphere has a radius R2 = 3 4 R1, but carries the same ch
Blizzard [7]

Answer:

The ratio of electric field is 16:9.

Explanation:

Given that,

Radius R_{2}=\dfrac{3}{4}R_{1}

Charge = Q

We know that,

The electric field is directly proportional to the charge and inversely proportional to the square of the distance.

In mathematically term,

E=\dfrac{kQ}{R^2}

Here, E\propto\dfrac{1}{R^2}

We need to calculate the ratio of electric field

Using formula of electric field

\dfrac{E_{2}}{E_{1}}=\dfrac{R_{1}^2}{R_{2}^2}

Put the value into the formula

\dfrac{E_{2}}{E_{1}}=\dfrac{(4R_{1})^2}{(3R_{1})^2}

\dfrac{E_{2}}{E_{1}}=\dfrac{16}{9}

Hence, The ratio of electric field is 16:9.

5 0
4 years ago
A force is acting on each of the objects below.
OlgaM077 [116]

Answer:

D

Explanation:

The forces have the same magnitude (3N), but different directions.  So they are different.

8 0
3 years ago
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