Ask question

Ask question

All categories

marshall27 [118]

3 years ago

15

Why is the composition of the vapor different from the composition of the solution?

1 answer:

BaLLatris [955]3 years ago

8 0

If there is solution with nonvolatile solute (<span>substance that does not readily </span>evaporate<span> into a </span>gas) <span>only the pure vapor of the solvent is present above the solution and solute stays in solution and do not enters vapor above solution. This is because nonvolatile solute has slow rate of evaporation and low vapore pressure.
If solution has two volatile components, composition of the vapor depends on vapor pressures of the components according </span><span>Raoult's Law.</span>

You might be interested in

The most common form of energy encountered in chemical reactions is _____. Select one:

Svetllana [295]

The answer is b heat

3 0

2 years ago

A supercell thunderstorm may have a distinctive shape like _____.

liq [111]

D. Pinwheel probably because think it’s a thunderstorm and supercells mean they are super big thunderstorms so I guess D

8 0

3 years ago

2. A chemical analysis of a sample provides the following elemental data:

Vadim26 [7]

Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

3 0

1 year ago

Any two objects that have Mass will also have which type of force between them

saul85 [17]

Gravitational <span>force between them</span>

5 0

3 years ago

Consider the following equilibrium:

Ainat [17]

<u>Answer: </u>The equation which is wrong is $K_p=K_c(RT)^{-5}$

<u>Explanation:</u>

For the given reaction:

$4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)$

The expression for $K_c\text{ and }K_p$ is given by:

$K_c=\frac{1}{[O_2]^3}$

$K_p=\frac{1}{[O_2]^3}$

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between $K_p\text{ and }K_c$ is given by the expression:

$K_p=K_c\times (RT)^{\Delta n_g}$

where,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

$\Delta n_g$ = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for $K_p$ is:

$K_p=K_c\times (RT)^{-3}$

Therefore, the equation which is wrong is $K_p=K_c(RT)^{-5}$

7 0

3 years ago