Question

Mechano, the evil robot cat, has captured the mous

Answer 1

Answer:

a) potential energy in the spring = 1.8225 J

b) Jerry's speed = 2.744 m/s

Explanation:

a) The spring constant, k = 1800 N/m

The rest length of the spring, $L_{0} = 0.0550 m$

The launch length, $L_{f} = 0.100 m$

The potential energy of each spring is , $PE = 0.5 k(\triangle x)^{2}$

$\triangle x = 0.1 - 0.055 = 0.045 m$

$PE = 0.5 * 1800* 0.045^{2}$

PE = 1.8225 J

b) To get Jerry's speed, use the law of energy conservation

PE energy in the string = KE of the robot

$KE = 0.5mv^{2}$

PE in the spring = 1.8225 J

$1.8825 = 0.5 mv^{2} \\1.8825 = 0.5 * 0.5 v^{2} \\1.8825 = 0.25 v^{2} \\ v^{2} = 1.8825/0.25\\v^{2} = 7.53$

v = 2.744 m/s