Answer:
a) 
.
b) 
.
Explanation:
a) What is the speed of the rock just before it hits the street?
From Kinematics we have 
.
If we take the top of the roof as the position 
, then
and we have (also, 
) :
⇒ 
⇒ .
b) How much time elapses from when the rock is thrown until it hits the street?
From Kinematics we have 
When the rock touches the ground:
With a minus sign to indicate the vector velocity points down.
(remember that 
)
in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.
your temp should be converted in kelvin
variables:
p1=3.0×10^6 n/m^2
t1= 270k
just add 273 to your celcius
p2= ? your solving for this
t2= 315k
then you set up the equation
(3.0×10^6)/270= (x)(315)
you then cross multiply
(3.0×10^6)315=270x
distribute the 315 to the pressure.
9.45×10^8=270x then you divide 270 o both sides to get
answer
3.5×10^6 n/m^2
Explanation:
Below is an attachment containing the solution.
Answer:
<h3>The binding energy of sodium Na=<em>5.407791×10⁹J</em></h3>
Explanation:
<h3>Greetings !</h3>
Binding energy, amount of energy required to separate a particle from a system of particles or to disperse all the particles of the system. Binding energy is especially applicable to subatomic particles in atomic nuclei, to electrons bound to nuclei in atoms, and to atoms and ions bound together in crystals.
<h2>Formula : Eb=(Δm)c²</h2><h3>where:Eb= binding energy</h3><h3> .Δm= mass defect(kg)</h3><h3> c= speed of light 3.00×10⁸ms¯¹</h3><h2 /><h3>
<u>Given</u><u> </u><u>values</u></h3>
- m= 18.02597
- c=3.00×10⁸ms¯¹
<h3><u>required </u><u>value</u></h3>
<h3><u>Solution:</u></h3>
- Eb=(Δm)c²
- Eb=(18.02597)*(3.00*10⁸ms¯¹
- Eb=5.407791*10⁹J
