Answer:
2.21 x 10⁻⁷m⁻¹
Explanation:
Given parameters:
Energy of the photon = 9.02 x 10⁻¹⁹J
Unknown:
Wavelength of the photon = ?
Solution;
The wavelength and energy of a photon are related using the expression below;
E =
h is the Planck's constant = 6.63 x 10⁻⁴m²kg/s²
c is the speed of light
E is the energy
h c = E x wavelength
Wavelength =
=
Wavelength = 2.21 x 10⁻⁷m⁻¹
The equation that shows the formation of chromium (ii) ion from neutral chromium atom is as follow
Cr ---> cr^2+ + 2e-
Cr^2+ is the chromium ion with oxidation state of two which is one of the common ion of chromium. Other common ion of chromium include chromium of oxidation state 6 and 3
Answer:
in the attached image is the reaction mechanism.
Explanation:
The first reaction (reaction 1) shown in the attached image is the Wolff-Kishner reduction, which is characterized when the carbonyl is reduced to an alkane in the presence of a hydrazine and a base. In reaction 1, the aldehyde reacts with hydrazine to produce oxime. This mechanism begins with the attack of the amine on the carbonyl group. Proton exchange happens and the water leaves the molecule.
In reaction 2, the KOH is deprotoned in nitrogen and organized to form the bond between the nitrogen molecule. this deprotonation releases the nitrogen gas
Answer:
The answer to your question is empirical formula Al₃O₉S
Explanation:
Data
Al = 31.5 %
O = 56.1 %
S = 12.4 %
Process
1.- Look for the atomic masses of the elements
Al = 27 g
O = 16
S = 32
2.- Represent the percentages as grams
Al = 31.5 g
O = 56.1 g
S = 12.4 g
3.- Convert these masses to moles
27 g of Al ----------------- 1 mol
31.5 g ---------------------- x
x = 1.17 moles
16 g of O ---------------- 1 mol
56.1 g of O ------------- x
x = 3.5 mol
32 g of S --------------- 1 mol
12.4 g of S ------------- x
x = 0.39 moles
4.- Divide by the lowest number of moles
Al = 1.17 / 0.39 = 3
O = 3.5 / 0.39 = 8.9 ≈ 9
S = 0.39 / 0.39 = 1
5.- Write the empirical equation
Al₃O₉S