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OleMash [197]
3 years ago
15

How does nuclear energy work? Explain

Physics
1 answer:
fgiga [73]3 years ago
6 0
There are many processes to get nuclear energy. Nuclear energy is basically energy from an atom. For example fission is where the nucleus of an atom ( typically radioactive atoms ) gets split then energy is released ( typically heat). And in radioactive decay radiation is released from an radioactive atom. Hope this helps
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A rigid tank initially contains 1.4 kg saturated liquid water at 200◦C. At this state, 25 percent of the volume is occupied by w
rjkz [21]

Answer:

(a) Volume of the tank is 6.47\times 10^{- 3}\ m^{3}

(b) Temperature is 371^{\circ}C

Pressure is 21.3 kPa

(c) The change in internal energy is 1373.54 kJ/kg

Solution:

As per the question:

Mass of liquid in the tank, m = 1.4 kg

Temperature, T = 200^{\circ}C

Volume occupied by water, V = 25%V_{t} = 0.25V_{t}

Volume occupied by air, V' = 75%V_{t}

where

V_{t} = Volume of tank

Now,

(a) In order to calculate the volume of the tank, we make use of the steam table for specific volume at  as given temperature:

At 200^{\circ}C, the specific volume, v = 0.001157m^{3}/kg

At 200^{\circ}C, the internal energy, u = 850.46 kJ/kg

Now,  Volume of water, V = mv = 1.4\times 0.001157 = 1.62\times 10^{- 3} m^{3}

Thus

V = 0.25V_{t}

V_{t} = \frac{1.62\times 10^{- 3}}{0.25} = 6.47\times 10^{- 3}\ m^{3}

(b) For the final temperature and pressure, we calculate the specific volume, v' and then find the corresponding temperature and pressure from the steam table:

v' = \frac{V_{t}}{m} = \frac{6.47\times 10^{- 3}}{1.4} = 4.63\times 10^{- 3}\ m^{3}/kg

The corresponding temperature to this specific volume, T' = 371^{\circ}C

The corresponding pressure to this specific volume, P' = 21.3 kPa

The corresponding internal energy to this specific volume, u' = 2224 kJ/kg

(c) The change in the internal energy of water is given by:

\Delta U = u' - u = 2224 - 850.46 = 1373.54 kJ/kg

3 0
3 years ago
Hii:) anyone able to explain and help me with this question?
Assoli18 [71]

Answer:

No

Explanation:

The equation of state for ideal gases tells that:

pV=nRT

where

p is the gas pressure

V is the gas volume

n is the number of moles of the gas

R is the gas constant

T is the absolute temperature

In this problem, we have a fixed mass of gas. This means that the number of moles of the gas, n, does not change; also, the volume V remains the same, and R is a constant, this means that

p\propto T

So, as the pressure increases, the temperature increases.

However, here we want to understand what happens to the average distance between the molecules.

We have said previously that the number of moles n does not change: and therefore, the total number of molecules in has does not change either.

If we consider one dimension only, we can say that the average distance between the molecules is

d=\frac{L}{N}

where L is the length of the container and N the number of molecules. Since the volume of the container here does not change, L does not change, and since N is constant, this means that the average distance between the molecules remains the same.

4 0
3 years ago
Nuclear sizes are expressed in a unit named<br><br> Magnetism at the centre of a bar magnet is
Illusion [34]
Nuclear size are measured in a unit called fermi
Magnetism at the centre of a bar magnet is zero, because there is no magnetism at all in the centre
Hope this helps :) 
3 0
4 years ago
Read 2 more answers
The electric force between two charged balloons is 0.16 newtons. If the distance between them is doubled, what will the new forc
lara31 [8.8K]
<span>So we wan't to know what will the Coulomb force be between two charged baloons will be if we double the distance between the them and Fc=0.16N. The coulomb force between two charges is Fc=k*Q1*Q2/r^2. So we see from the equation that the magnitude of the force will be smaller as we increase the distance. So let's increase the distance from r to R=2r. If we input thai into the equation we get: Fc=k*Q1*Q2/R^2. Now: Fc=k*Q1*Q2/(2r)^2. And finally: Fc= k*Q1*Q2/4r^2. And if we factor out 1/4 we get: Fc=(1/4)*k*Q1*Q2/r^2. Now we can see that if we double the distance the magnitude of the force will be smaller for a factor of 1/4 or the magnitude of the force will be smaller 4 times. So finally the force is (1/4)*0.16N= 0.04N. So the correct answer is A. 0.04 newtons. </span>
4 0
4 years ago
Read 2 more answers
A wire carries a 2a current. what is the current in a second wire that delivers twice as much charge in the same amount of time?
Soloha48 [4]

Answer:

4A

Explanation:

Current is charge per time.  So if the second wire delivers twice as much charge in the same amount of time, it must have twice the current.

2 × 2A = 4A

7 0
3 years ago
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