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2 years ago

Which of the following would be the least reliable source of information?

Physics

1 answer:

Ksivusya [100]2 years ago

5 0

A weekly news magazine would be the least.

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What is the color of the stars with the highest surface temperature and what is the color of the stars with the lowest surface t

fenix001 [56]

It is a basic color like whit or yellow

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2 years ago

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An engineer has the task of producing an aluminum alloy with a density of 3.0 grams per cubic centimeter. She comes up with the

pochemuha

Answer:

The best option is for the following option m = 15 [g] and V = 5 [cm³]

Explanation:

We have that the density of a body is defined as the ratio of mass to volume.

$Ro =m/V$

where:

Ro = density = 3 [g/cm³]

Now we must determine the densities with each of the given values.

For m = 7 [g] and V = 2.3 [cm³]

$Ro=7/2.3\\Ro=3.04 [g/cm^{3} ]$

For m = 10 [g] and V = 7 [cm³]

$Ro=10/7\\Ro=1.42[g/cm^{3} ]\\$

For m = 15 [g] and V = 5 [cm³]

$Ro=15/5\\Ro=3[g/cm^{3} ]\\$

For m = 21 [g] and V = 8 [cm³]

$Ro=21/8\\Ro=2.625[g/cm^{3} ]\\$

5 0

2 years ago

Which of the following is not an application of Doppler technology?

allsm [11]

The correct answer to the question above is The third Option: C; ultrasound imaging of the liver. The ultrasound imaging of the liver is definitely not an application of Doppler technology.

Hope this helps! :)

8 0

3 years ago

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In an elastic head-on collision, a 0.60 kg cart moving at 5.0 m/s [W] collides with a 0.80 kg cart moving at 2.0 m/s [E]. The co

labwork [276]

Answer:

The answer is given below

Explanation:

u is the initial velocity, v is the final velocity. Given that:

$m_1=0.6kg,u_1=-5m/s(moving \ west),m_2=0.8kg,u_2=2m/s,k=1200N/m$

The final velocity of cart 1 after collision is given as:

$v_1=(\frac{m_1-m_2}{m_1+m_2})u_1+\frac{2m_2}{m_1+m_2}u_2\\ Substituting:\\v_1=\frac{0.6-0.8}{0.6+0.8} (-5)+\frac{2*0.8}{0.6+0.8}(2)= 5/7+16/7=3\ m/s$

The final velocity of cart 2 after collision is given as:

$v_2=(\frac{m_2-m_1}{m_1+m_2})u_2+\frac{2m_1}{m_1+m_2}u_1\\ Substituting:\\v_1=\frac{0.8-0.6}{0.6+0.8} (2)+\frac{2*0.6}{0.6+0.8}(-5)= 2/7-30/7=-4\ m/s$

b) Using the law of conservation of energy:

$\frac{1}{2}m_1u_1+ \frac{1}{2}m_2u_2=\frac{1}{2}m_1v_1+\frac{1}{2}m_2v_2+\frac{1}{2}kx^2\\x=\sqrt{\frac{m_1u_1+m_2u_2-m_1v_1-m_2v_2}{k}}\\ Substituting\ gives:\\x=\sqrt{\frac{0.6*(-5)^2+0.8*2^2-(0.6*3^2)-(0.8*(-4)^2)}{1200}}=\sqrt{0}=0\ cm$

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3 years ago

The layer of leaves that blocks most of the sunlight from reaching the ground in the rain forest is called the _____.

love history [14]

The answer should be canopy.

4 0

2 years ago

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