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andrezito [222]
3 years ago
15

A bug travels at the rate of 3.0 miles per hour. How fast is this in um/nsec? Hint: 2.54cm = 1 inch and 1 mile = 5,280 feet

Chemistry
1 answer:
kirza4 [7]3 years ago
4 0
Note that
1 mi = 1609.34 m = 1609.34 x 10⁶ um
1 h = 3600 s = 3600 x 10⁹ ns

Therefore the speed of the bug is
 (3.0 mi/h)*(1609.34x10⁶ um/mi)*(1/3600x10⁹ h/ns)
(3.0 \,  \frac{mi}{h}) (1609.34\times10^{6}\, \frac{um}{mi} )( \frac{1}{3600\times 10^{9}}  \frac{h}{ns} ) =1.34\,\times 10^{-3} \,  \frac{um}{ns}

Answer: 1.34 \times 10^{-3} \,  \frac{\mu m}{ns}
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A 3.140 molal solution of NaCl is prepared. How many grams of NaCl are present in a sample containing 2.692 kg of water
S_A_V [24]

Answer:

494.49 g of NaCl.

Explanation:

Data obtained from the question include the following:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mass of NaCl =.?

Next, we shall determine the number of mole of NaCl in the solution.

Molality is simply defined as the mole of solute per unit kilogram of solvent. Mathematically, it is expressed as

Molality = mole of solute /Kg of solvent

With the above formula, we can obtain the number of mole NaCl in the solution as follow:

Molality of NaCl = 3.140 m

Mass of water = 2.692 kg

Mole of NaCl =..?

Molality = mole of solute /Kg of solvent

3.140 = mole of NaCl /2.692

Cross multiply

Mole of NaCl = 3.140 x 2.692

Mole of NaCl = 8.45288 moles

Finally, we shall covert 8.45288 moles of NaCl to grams. This can be obtained as follow:

Mole of NaCl = 8.45288 moles

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl =.?

Mole = mass /Molar mass

8.45288 = mass of NaCl /58.5

Cross multiply

Mass of NaCl = 8.45288 × 58.5

Mass of NaCl = 494.49 g.

Therefore, 494.49 g of NaCl are present in the solution.

8 0
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what mass of chromium (III) sulfide is produced from the reaction of 13.2 g of sulfur with excess chromium?
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Explanation:

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c) a compound

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6.23 x 10^23 molecules

Explanation:

First find the number of moles of BH3 from the information given. We know the amount of grams present and we can find the molar mass which is 13.84.

We know that moles is grams divided by molar mass so we get 14.32/13.84 which is 1.03 moles.

Finally, to figure out the number of molecules, we multiply 1.03 by Avogadro's number which is 6.022x10^23 and we get 6.23x10^23 molecules.

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